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monitta
3 years ago
15

Mr. Case is placing boxes along one of the walls in his attic. If the wall is 11 1⁄3 feet long and each box is 2 1⁄2 feet long,

how many boxes can he fit along the attic wall?
Mathematics
1 answer:
rosijanka [135]3 years ago
4 0

Answer: he can fit 4 boxes in his attic

Step-by-step explanation:

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In a naval engagement, one-third of the fleet was captured, one-sixth was sunk, and two ships were destroyed by fire. One-sevent
Otrada [13]

Answer:

60 ships.

Step-by-step explanation:

Let the total number of ships in the naval fleet be represented by x

One-third of the fleet was captured = 1/3x

One-sixth was sunk = 1/6x

Two ships were destroyed by fire = 2

Let surviving ships be represented by y

One-seventh of the surviving ships were lost in a storm after the battle = 1/7y

Finally, the twenty-four remaining ships sailed home

The 24 remaining ships that sailed home =

y - 1/7y = 6/7y of the surviving fleet sailed home.

Hence

24 = 6/7y

24 = 6y/7

24 × 7/ 6

y = 168/6

y = 28

Therefore, total number of ships that survived is 28.

Surviving ships lost in the storm = 1/7y = 1/7 × 28 = 4

Total number of ships in the fleet(x) =

x = 1/3x + 1/6x + 2 + 28

Collect like terms

x - (1/3x + 1/6x) = 30

x - (1/2x) = 30

1/2x = 30

x = 30 ÷ 1/2

x = 30 × 2

x = 60

Therefore, ships that were in the fleet before the engagement were 60 ships.

3 0
3 years ago
Can someone help? I don't understand the equasion
Alika [10]

Answer:

a = 1/6

Step-by-step explanation:

To solve, divide both sides by 5 1/4

a = 7/8 / (5 1/4)

a = (7/8) / (21/4)

a= 7/8 * 4/21

a= 28/168

a= 1/6

8 0
3 years ago
Solve x^2 – 8x + 41 = 0 for x.
icang [17]
<span>\displaystyle x^2 - 8x + 41 = 0 \\\\ \Delta=b^2-4ac \\ \Delta=(-8)^2-4\cdot1\cdot41 \\ \Delta=64-164 \\ \Delta=-100 \\ \\ X_{1,2}= \frac{-b\pm i \sqrt{-\Delta} }{2a} = \frac{8 \pm 10i}{2} \\ \\ X1=4-5i \\ \\ X2=4+5i</span>
5 0
3 years ago
What is the product of the 2 solutions of the equation x^2+3x-21=0
Advocard [28]
X²+3x-21=0

1) we solve this square equation:
x=[-3⁺₋√(9+84)] / 2=(-3⁺₋√93)/2
We have two solutions:
x₁=(-3-√93)/2
x₂=(-3+√93)/2

2) we compute the product of the 2 solutions found.
[(-3-√93)/2][(-3+√93)/2] =(-3-√93)(-3+√93) / 4=
=(9-93)/4=-84/4=-21

Answer: the product of the 2 solutions of this equation is -21
3 0
3 years ago
I need help! I forgot how to do this problem
Nataly [62]

Answer:

C.

Step-by-step explanation:

8 0
3 years ago
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