All categories

3 years ago

If KM = 32 units, KL = 3x+6 and LM= 11 units, what is the value of x?

Mathematics

1 answer:

Rus_ich [418]3 years ago

7 0

Answer:

Step-by-step explanation:

|<------------------- 32 units ---------------->|

K-----------------------L-------------------------M

3x + 6 11

KL + LM = KM

3x + 6 + 11 = 32

3x = 32 - 11 - 6

x = 15 / 3

x = 5 units

You might be interested in

Sally went to the clearance rack at a department store and found a shirt she wanted to buy. The shirt was $36.00 and is on sale

jeka57 [31]

Answer:

33.34%.

Step-by-step explanation:

Given that,

The actual price of the shirt = $36

Price on sale = $24

We need to find the percent of the decrease. The formula for the percentage is given by :

$\%=\dfrac{|\text{actual value-estimated value}|}{\text{actual value}}\times 100$

Putting all the values,

$\%=\dfrac{24-36}{36}\times 100\\\\=33.34\%$

So, the percentage decrease in the price of the shirt is 33.34%.

6 0

3 years ago

How do I solve problems like this? <br><br> X + 1/2 = 4/6

andrezito [222]

Answer:

1/3

Step-by-step explanation:

pic bleow

also can u help or someone

draw three cells in parallel, two light bulbs (loads) in series, with one switch.

5 0

2 years ago

In the figure, triangle CAE is an enlargement of triangle CBD with scale factor of 4/3. The area of the smaller triangle is 9cm2

balandron [24]

Answer:

16 cm^2

Step-by-step explanation:

Given

$\triangle CAE$ -- Bigger Triangle

$\triangle CBD$ -- Smaller Triangle

$k = \frac{4}{3}$ --- Scale factor

Area of CBD = 9

Required

Determine the area of CAE

The area of triangle CBD is:

$A_1 = \frac{1}{2}bh$

$\frac{1}{2}bh = 9$

The area of CAE is:

$A_2 = \frac{1}{2}BH$

Where:

$B = \frac{4}{3}b$ and

$H = \frac{4}{3}h$

The above values is the dimension of the larger triangle (after dilation).

So, we have:

$A_2 = \frac{1}{2}*\frac{4}{3}b * \frac{4}{3} * h$

$A_2 = \frac{1}{2}*\frac{4}{3} * \frac{4}{3} *b* h$

$A_2 = \frac{1}{2}*\frac{16}{9} *b* h$

Re-order

$A_2 = \frac{16}{9}*\frac{1}{2}* b* h$

$A_2 = \frac{16}{9}*\frac{1}{2}bh$

Recall that:

$\frac{1}{2}bh = 9$

$A_2 = \frac{16}{9}*9$

$A_2 = 16$

Hence, the area is 16 cm^2

3 0

3 years ago

The measures of the angles of a triangle are shown in the figure below. Solve for x.

tino4ka555 [31]

Answer:

The vale of x=4

Step-by-step explanation:

We know that the sum of angles of a triangle = 180°

Given

(3x+13)

(8x+14)

109°

Thus, the equation becomes

(3x+13) + (8x+14) + 109° = 180°

11x + 27 + 109° = 180°

11x = 180°- 109° - 27

11x = 44

x = 4

Thus, the vale of x=4

6 0

3 years ago

The value of (k) is less than or equal to 2500

Volgvan

Answer:

k< or equal to 2500

Step-by-step explanation:

8 0

3 years ago