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3 years ago

Factor completely 5x2 − 40. 5(x 8)(x − 8) 5(x2 − 8) 5(x 8)(x − 5) prime

Mathematics

2 answers:

yuradex [85]3 years ago

4 0

5x^2 - 40 = 5(x^2 - 8)

EastWind [94]3 years ago

3 0

Answer:

The factors of the expression 5x² − 40 is 5 (x²- 8).

Step-by-step explanation:

As the expression given in the question as follow .

= 5x² − 40

Taking 5 as the common part of the above expression.

Thus the expression becomes

= 5 (x² − 8)

Therefore the factors of the expression 5x² − 40 is 5(x²- 8).

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If log2 5 = k, determine an expression for log32 5 in terms of k.

lukranit [14]

Answer:

$log_3_2(5)=\frac{1}{5} k$

Step-by-step explanation:

Let's start by using change of base property:

$log_b(x)=\frac{log_a(x)}{log_a(b)}$

So, for $log_2(5)$

$log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)$

Now, using change of base for $log_3_2(5)$

$log_3_2(5)=\frac{log(5)}{log(32)}$

You can express $32$ as:

$2^5$

Using reduction of power property:

$log_z(x^y)=ylog_z(x)$

$log(32)=log(2^5)=5log(2)$

Therefore:

$log_3_2(5)=\frac{log(5)}{5*log(2)}=\frac{1}{5} \frac{log(5)}{log(2)}\hspace{10}(2)$

As you can see the only difference between (1) and (2) is the coefficient $\frac{1}{5}$ :

So:

$\frac{log(5)}{log(2)} =k\\$

$log_3_2(5)=\frac{1}{5} \frac{log(5)}{log(2)} =\frac{1}{5} k$

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