The correct option is (C) Grow in conjunction with shedding of their exoskeleton.
The number of species in the superphylum Ecdysozoa is staggering. This is due to the presence of two of the most varied animal phyla, the Phylum Nematoda (which includes roundworms) and the Phylum Arthropoda (the arthropods).
<h3>
What do nematodes and arthropods have in common?</h3>
- The tough external covering of Ecdysozoans, known as the cuticle, is their most obvious identifying characteristic. These animals are shielded from predators, water loss, and other elements of their environment by the cuticle, which also acts as a robust yet flexible exoskeleton.
- Every member of this superphylum undergoes periodic molting, or cuticle shedding, as they develop. They produce a fresh cuticle after molting that will protect them until their subsequent growth phase.
- The process of molting and cuticle replacement, known as ecdysis, is how the superphylum earned its name.
Learn more about the Phylum Arthropoda with the help of the given link:
brainly.com/question/14184371
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Answer;
Forward chaining and backward chaining are Similar in that;
Both are used to teach a chain of behaviors.
Both use procedures,
Both teach one behavior at a time and chain the behaviors together.
Both procedures use prompting and fading to teach each component
Explanation;
-Backward chaining; When you teach the last stimulus-response component first. Then teach the next to last component and so on.
-Forward chaining; Teach the first stimulus-response component first. Then teach the second component and so on
Repeat the epinephrine injection after consulting with medical control.
Answer:
16/64 = 1/4
Explanation:
This is a typical trihybrid cross involving three genes T, P and Y. A plant with genotype TTPpYy is crossed with a plant recessive for all traits (ttppyy).
According to Mendel's law of independent assortment, each allele for each gene will get sorted into the following 8 gametes with only 4 different: TPY, TPy, TpY, Tpy, TPY, TPy, TpY and Tpy.
The recessive parent, ttppyy will produce tpy, tpy, tpy, tpy, tpy, tpy, tpy and tpy.
Hence, using a punnet square, 64 offsprings will be produced with only 16 of them heterozygous dominant for the three traits with genotype (TtPpYy). Hence, proportion is 16/64 equivalent to 1/4.
I believe the term for two similar chromosomes would be homologous chromosomes.
