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2 years ago

Solve please!! Please hurry this is due today!!

Mathematics

2 answers:

dezoksy [38]2 years ago

5 0

Answer:

X=2 and y=5

Step-by-step explanation:

5=-4+9 True

5=8-3 True

kondaur [170]2 years ago

3 0

X = 2 and y = 5 !! :)

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In 2013 nyc had 66.37 inches of precipitation what is that amount of precipitation to the nearest inch

V125BC [204]

Since we are rounding to the nearest inch, we want to look at the tenths place. The rule for rounding is 5 and up, we round up, 4 and below, stay. Since 3 is below 5, we stay. Therefore your answer should be 66 inches of precipitation. Hope this helps!

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2 years ago

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Larry is 10 years old and his sister is 7 years old. In how many years time will there total age be 25 years?

maks197457 [2]

In the next 25 years, Larry will be 35 years old, while his sister will be 3 years less than him which is 32 years old for his sister, since his sister is 3 years younger.

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3 years ago

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What is the approximate area of a circle with a radius of 30

amid [387]

Answer:

Step-by-step explanation:

Area of circle = π r²

r = 30

30² = 900

π = 3.14 or ≈ 3

A ≈ 900 × 3

A ≈ 2700

so C at 2830 is closest to the answer

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2 years ago

You operate a gaming Web site, www.mudbeast.net, where users must pay a small fee to log on. When you charged $3 the demand was

Doss [256]

Answer:

A) The linear relation between price and demand is:

$d=-550x+2750$

The revenue R is:

$R=-550x^2+2750x$

B) The profit functionP is:

$P=-550x^2+2750x-30$

C) The largest monthly profit is obtained with a log-on fee of $2.5 per month. This corresponds to a profit of $3407.5.

Step-by-step explanation:

We have a site where the number of log-ons depends on our monthly fee. A linear relation is established between the price (log-on fee) and the number of log-ons.

We have two points for this linear relationship:

At price x=3, the demand is d=1100.
At price x=2.5, the demand is d=1375.

We will model the relation:

$d=mx+b$

We can calculate the slope m as:

$m=\dfrac{\Delta d}{\Delta x}=\dfrac{d_2-d_1}{x_2-x_1}=\dfrac{1375-1100}{2.5-3}\\\\\\m=\dfrac{275}{-0.5}=-550$

Then, replacing one point in the linear equation, we can calculate the intercept b:

$d_1=mx_1+b\\\\1100=(-550)\cdot 3+b\\\\1100=-1650+b\\\\b=1100+1650=2750$

Then, the linear relation between demand and price is:

$d=-550x+2750$

The revenue R can be expressed as the multiplication of the price and the demand:

$R=x\cdot d=x(-550x+2750)=-550x^2+2750x$

If we have a fixed cost of $30 per month, the profit P is:

$P=R-FC=-550x^2+2750x-30$

We can maximize the profit by deriving the profit function and making it equal to zero.

$\dfrac{dP}{dx}=0\\\\\\\dfrac{dP}{dx}=-550(2x)+2750(1)=0\\\\\\-1100x+2750=0\\\\x=\dfrac{2750}{1100}=2.5$

This corresponds to a profit of:

$P(2.5)=-550(2.5)^2+2750(2.5)-30\\\\P(2.5)=-550\cdot 6.25+6875-30\\\\P(2.5)=-3437.5+6875-30\\\\P(2.5)=3407.5$

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3 years ago

X- 6= -10<br><br> what does x=

melamori03 [73]

Answer:-5

Step-by-step explanation:

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2 years ago

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