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zhannawk [14.2K]
2 years ago
5

9y%20%2B%20y6%20%3D%20" id="TexFormula1" title="x = 7 \\ y = 4 \\ \\ 28 + 43 + xy + 9y + y6 = " alt="x = 7 \\ y = 4 \\ \\ 28 + 43 + xy + 9y + y6 = " align="absmiddle" class="latex-formula">
try to find the answer ​
Mathematics
2 answers:
laila [671]2 years ago
8 0
71 + xy + 15y

hope it helps youuuuü
TiliK225 [7]2 years ago
7 0

Answer:

159. Is your ANS..........

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Find the equation of the line passing through (3,4), (-1,-2).
Kryger [21]

Answer:

(y-(-2))/(x-(-1)= (-2-4)/(-1-3)

(y+2)/(x+1)= (-6)/(-4)

(y+2)/(x+1)= (3/2)

Cross multiplying

2y+4= 3x+3

3x-2y-1=0

7 0
3 years ago
A printer takes 5mins to print 90 copies of a repor. At this rate, how many copies of the same report can it print in 1/2 hours
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What is the answer to 2/9 x 2 9/10
Minchanka [31]
The answer to your problem is 58/90
7 0
3 years ago
Date
ololo11 [35]

Answer: 22%, 0.22, 11/50

Step-by-step explanation:

As a percent, 44/200 × 100 =

0.22 × 100

= 22%

As a decimal, divide 44 by 200 using a calculator; 44÷200 = 0.22

As a fraction in the simplest form, 44/200, we find the greatest common factor for the numerator and denominator, which is 4, divide 4 by numerator = 11

Divide 4 by denominator = 50

44/200 as a fraction = 11/50

5 0
3 years ago
The function f(t) =16t 2 + 248 models the height f(t) in feet of a stone t seconds after it is dropped from the edge of a vertic
Hatshy [7]

Answer:

The time it takes for the stone to reach the ground is 3.94 s. This answer is correct.

Step-by-step explanation:

I believe there's a mistake in the equation shown, the acceleration (number that multiplies t²) should be negative, since the stone is falling, therefore I'll answer assuming it's -16 instead of 16, otherwise there would be no real solution to the equation.

In order to calculate how long it'll take for the stone to hit the ground we must make f(t) = 0 and find the time "t" that makes the equation valid, so we have:

f(t) = -16t² + 248 = 0

-16t² = -248

t² = -248/(-16) = 15.5

t = sqrt(15.5) = 3.94

7 0
3 years ago
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