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3 years ago

Can i get help on 1-10 or on a couple

Mathematics

1 answer:

Step2247 [10]3 years ago

5 0

1) 1,2,3,4,6,9,12,18,13

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Geometry question,. Someone please help me!!

KATRIN_1 [288]

Answer:

I think its 23o

Step-by-step explanation:

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3 years ago

Find the GCF 18x three to the third power and 30x to the fifth power

Juliette [100K]

18x^3 = 6x^3 (3)
30x^5 = 6x^3 (5x^2)

so
GCF = 6x^3

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4 years ago

2x-4y=10<br> slope of the line?

lara31 [8.8K]

Answer:

The slope is 1/2

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3 years ago

Read 2 more answers

Ezpress 3x + 11/x² + 6x + 9<br>as partial fractions,

andreev551 [17]

Answer:

$\frac{3}{x + 3} + \frac{2}{(x+3)^2}$

Step-by-step explanation:

Given

$\frac{3x + 11}{x^2 +6x + 9}$

Required

Express as partial fraction

$\frac{3x + 11}{x^2 +6x + 9}$

Expand the numerator

$\frac{3x + 11}{x^2 +3x +3x+ 9}$

Factorize

$\frac{3x + 11}{x(x +3) +3(x+ 3)}$

Factor out x + 3

$\frac{3x + 11}{(x +3)(x+ 3)}$

$\frac{3x + 11}{(x +3)^2}$

As a partial fraction, we have:

$\frac{3x + 11}{(x +3)^2} = \frac{A}{x + 3} + \frac{B}{(x+3)^2}$

Take LCM

$\frac{3x + 11}{(x +3)^2} = \frac{A(x+3) + B}{(x + 3)^2}$

Cancel out (x + 3)^2 on both sides

$3x + 11 = A(x+3) + B$

Open bracket

$3x + 11 = Ax+3A + B$

By comparison, we have:

$Ax = 3x$ ===> $A = 3$

$3A + B = 11$

Substitute 3 for A

$3*3 + B = 11$

$9 + B = 11$

Solve for B

$B = 11-9$

$B =2$

Substitute: $A = 3$ and $B =2$ in

$\frac{3x + 11}{(x +3)^2} = \frac{A}{x + 3} + \frac{B}{(x+3)^2}$

$\frac{3x + 11}{(x +3)^2} = \frac{3}{x + 3} + \frac{2}{(x+3)^2}$

Hence, the partial fraction is:

$\frac{3}{x + 3} + \frac{2}{(x+3)^2}$

7 0

2 years ago

A regular pentagon is inscribed in ur let of radius 8cm. find the length of one side of the polygon

Sergio039 [100]

9514 1404 393

Answer:

9.404 cm

Step-by-step explanation:

A regular polygon with n sides inscribed in a circle of radius r will have a side length given by ...

s = 2r·sin(180°/n)

For r = 8 and n = 5, this gives a side length of ...

s = 2·8·sin(180°/5) = 16·sin(36°) ≈ 9.404 . . . cm

4 0

3 years ago