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nydimaria [60]
3 years ago
13

What is the probability that a point chosen at random in the given figure will be inside the larger triangle and outside the sma

ller triangle?
Mathematics
2 answers:
Blababa [14]3 years ago
8 0
(Larger area - smaller area) / larger area
the dude's correct
just restating the answer cuz its right
Dmitriy789 [7]3 years ago
7 0
No picture, but quite simple question...

The probability of choosing a random spot inside the larger triangle and outside the smaller triangle is:

(Larger area - smaller area) / larger area
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garik1379 [7]

f(x) = \cos^2(3x^3)\\f'(x) = \frac{d}{dx}[\cos^2(3x^3)]\\= 2\cos(3x^3) \cdot \frac{d}{dx}[cos(3x^3)]\\= 2\cos(3x^3) \cdot (-\sin(3x^3)) \cdot \frac{d}{dx}[3x^3]\\= 2\cos(3x^3) \cdot (-\sin(3x^3)) \cdot 9x^2\\= -18x^2\cos(3x^3)\sin(3x^3)

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3 years ago
Find the surface area of this triangular prism. Be sure to include the correct unit in your answer.
Alina [70]
It is 245m thank me later
4 0
3 years ago
How are the formulas for the area of a rectangle and the area of a triangle alike and different?
rodikova [14]

Answer:

A diagonal of a rectangle separates the rectangle into two congruent triangles. The area of each triangle is one-half the area of the rectangle. So, the area A of a triangle is given by the formula A=12bh where b is the base and h is the height of the triangle.

Step-by-step explanation:

5 0
3 years ago
Bacteria culture A culture of the bacterium Rhodobacter sphaeroids initially had 30 bacteria and t hours later increases at a ra
Sloan [31]

Complete Question

Bacteria culture A culture of the bacterium Rhodobacter sphaeroids initially had 30 bacteria and t hours later increases at a rate of 2e^2t 1 bacteria per hour. Find the population size after four hours

Answer:

3010

Step-by-step explanation:

We were given the rate: 2e^2t

Step 1

We would integrate

P = Population

dP/dt = 2e^2t

dP =( 2e^2t) dt

∫dP = ∫ 2e^2t dt

P(t) = (2e^2t)/2 + C

P(t) = e^2t + C

Step 2

We solve for C

The culture initially has 30 bacteria

When t = 0

P(0) = 30

P(0) = e^2t + C

30 = e^2× 0 + C

30 = 1 + C

C = 30 - 1

C = 29

Step 3

Find the population size after four hours

t = 4, C = 29

P(t) = e^2t + C

P(4) = e^2 × 4 + 29

P(4) = e^8 + 29

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Approximately = 3010 bacteria

7 0
3 years ago
Plsssssssssssssss help
viktelen [127]

Answer:

                       D?

Step-by-step explanation:

                that my opinion but if i'm wrong i apologize

6 0
3 years ago
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