X+y=13and x-y=2 what is the value of x^2-y^2

2 answers:

7 0

Just a quick sidenote.

$\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-------------------------------\\\\
x+y=13\qquad x-y=2
\\\\\\
x^2-y^2\implies (x+y)(x-y)\implies (13)(2)$

Kazeer [188]3 years ago

3 0

X+y=13
x-y=2

Add the equations (elimination method)

x+y+x-y=13+2
2x=15
x=7.5

Plug in this y value

7.5-y=2
-y=-5.5
y=5.5

Plug in both the x and y values into the equation asked for

(7.5)^2-(5.5)^2
56.25-30.25

Final answer: 26

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<h2>Hello!</h2>

The answers are:

$MaximumDistance=1200.1ft\\MinimumDistance=1199.9ft$

Since we are given the margin of error and it's equal to ±0.1 feet, and we know the surveyed distance, we can calculate the maximum and minimum distance. We must remember that margin of errors usually involves and maximum and minimum margin of a measure, and it means that the real measure will not be greater or less than the values located at the margins.

We know that the surveyed distance is 1200 feet with a margin of error of ±0.1 feet, so, we can calculate the maximum and minimum distances that the reader could assume in the following way:

$MaximumDistance=ActualDistance+0.1feet\\\\MaximumDistance=1200feet+0.1feet=1200.1feet$