Question

Please help! find x and y

Answer 1

Answer:

Step-by-step explanation:

$\dfrac{3+x}3=\dfrac{20}5\\\\3+x = 4\cdot3\\\\x=12-3 \\\\x= 9$                               $\dfrac{4+y}4=\dfrac{20}5\\\\4+y= 4\cdot4\\\\y=16-4 \\\\y=12$

$\dfrac{3+x+u}3=\dfrac{60}5\\\\3+9+u=12\cdot3\\\\u=36-12 \\\\u=24$                      $\dfrac{4+y+v}4=\dfrac{60}5\\\\4+12+v=12\cdot4\\\\v=48-16 \\\\v=32$