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3 years ago

2+x-(3-z); use x=6, and z=1

Mathematics

2 answers:

tangare [24]3 years ago

8 0

2+6-(3-1)
2+ 6-2
2+ 4
= 6

Nataly_w [17]3 years ago

4 0

Answer:

Step-by-step explanation:

$2+x-(3-z)\\ x=6\\ z=1\\= 2+6-(3-1)\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:within\:parentheses}\:\left(3-1\right)\::\quad 2\\=2+6-2\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:2+6-2\:\\:\quad 6$

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A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the

Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

$D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{1}{455} = 0.0021$

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

$D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{36}{455} = 0.0791$

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

3 0

3 years ago

If the length of the minor axis of an ellipse is 6 units and the length of the major axis is 10 units, how far from the center a

Sedbober [7]

The distance from the center to where the foci are located exists 8 units.

<h3>How to determine the distance from the center?</h3>

The formula associated with the focus of an ellipse exists given as;

c² = a² − b²

Where c exists the distance from the focus to the center.

a exists the distance from the center to a vertex,

the major axis exists 10 units.

b exists the distance from the center to a co-vertex, the minor axis exists 6 units

c² = a² − b²

c² = 10² - 6²

c² = 100 - 36

c² = 64

$c = \sqrt{64}$

c = 8

Therefore, the distance from the center to where the foci are located exists 8 units.

To learn more about the Pythagorean theorem here:

brainly.com/question/654982

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1 year ago

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Inga [223]

Answer:

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2 years ago

The graph of the line y= 3 is a line that has which of the following characteristics?

vaieri [72.5K]

Answer:

Step-by-step explanation:

4 0

2 years ago

given a rectangle of length a and width b if A and B are both rational numbers would the perimeter be irrational or rational? Gi

Kitty [74]

The perimeter would be rational due to both the width and length being rational numbers. A rational number is a number that can be written as a fraction such as 8 it can be written as 8/1, but a irrational would be a decimal number which in this case there would be none because both length and width is rational number. For example, Lets say the width is 8 and the length is 10. once both are written into fraction form such as 8/1 and 10/1 we add them to get a perimeter of 18.
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8 0

3 years ago

2+x-(3-z); use x=6, and z=1​

2+x-(3-z); use x=6, and z=1