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3 years ago

Please answer correctly, work is optional.

Mathematics

2 answers:

kati45 [8]3 years ago

3 0

Answer: 0.845

Step-by-step explanation: 1.69 divided by two is 0.845

vagabundo [1.1K]3 years ago

3 0

Answer. 1.3 km

Explanation. To find the area of a square, multiply the base and the height. Because it is a square, we know that these two numbers would have to be the same. Therefore, this number has a square root. To find it, find the sq root of 1.69. The answer is 1.3. To test this, multiply 1.3 by 1.3, you get 1.69.

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from the top of an 800 foot tall car talk tower, tom sees a plane; the angle of elevation is 67 degrees. at the same instant tay

AlekseyPX

Answer:

Height of plane = 25971.7 meters

Step-by-step explanation:

let H =height of plane

Let x = distance ray to the point under the plane

800 foot = 245meters

1 mile = 1609meters.

Tan 81 = $\frac{H}{1609+x}$ -----------------------(1)

Tan 67 = $\frac{H-245}{x}$ -----------------------(2)

6.3134 = $\frac{H}{1609+x}$ ------------------------(3)

2.3556 = $\frac{H-245}{x}$ -----------------------(4)

from (3) and (4)

H = 10158.26 + 6.3134x ---------------(a)

H = 245 + 2.2336x ---------------(b)

equating both (a) and (b) we have:

9913.26 = 3.9576x

x = 2504.74

Subst. x = 2504.74 into (a)

H = 25971.7meters

8 0

3 years ago

Which point is a solution to the inequality shown in this graph

astra-53 [7]

Answer:

D: (1,5) Apex

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Need help asap need to get this done

djyliett [7]

Answer:

3:4

Step-by-step explanation:

8/6=4/3

12/9=4/3

16/12=4/3

5 0

3 years ago

The equation Ax+By=10 goes through the coordinates (6,5) and (-2,-5).What are the values of A and B

wolverine [178]

Given:

The equation $Ax+By=10$ goes through the coordinates (6,5) and (-2,-5).

To find:

The values of A and B.

Solution:

We have,

$Ax+By=10$

It goes through the coordinates (6,5) and (-2,-5). It means these points will satisfy the equation.

$A(6)+B(5)=10$

$6A+5B=10$ ...(i)

$A(-2)+B(-5)=10$

$-2A-5B=10$ ...(ii)

Adding (i) and (ii), we get

$(6A+5B)+(-2A-5B)=10+10$

$4A=20$

Divide both sides by 4.

$A=5$

Put A=5 in (i), we get

$6(5)+5B=10$

$30+5B=10$

$5B=10-30$

$5B=-20$

Divide both sides by 5.

$B=-4$

Therefore, the values of A and B are 5 and -4 respectively.

3 0

3 years ago

Find a particular solution to the nonhomogeneous differential equation y??+4y?+5y=?10x+e^(?x).

Firdavs [7]

Answer:

A) Particular solution:

$2x+\frac{1}{2}e^{-x}-\frac{8}{5}$

B) Homogeneous solution:

$y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))$

C) The most general solution is

$y=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))+2x+\frac{1}{2}e^{-x}-\frac{8}{5}$

Step-by-step explanation:

Given non homogeneous ODE is

$y''+4y'+5y=10x+e^{-x}---(1)$

To find homogeneous solution:

$D^{2}+4D+5=0\\D^{2}+4D+4-4+5=0\\\\(D+2)^{2}=-1\\D+2=\pm iD=-2 \pm i\\y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))---(2)$

To find particular solution:

$y_{p}=Ax+B+Ce^{-x}\\\\y'_{p}=A-Ce^{-x}\\y''_{p}=Ce^{-x}\\$

Substituting $y_{p},y'_{p},y''_{p}$ in (1)

$y''_{p}+4y'_{p}+5y_{p}=10x+e^{-x}\\Ce^{-x}+4(A-Ce^{-x})+5(Ax+B+Ce^{-x})=10x+e^{-x}\\$

Equating the coefficients

$5Ax+2Ce^{-x}+4A+5B=10x+e^{-x}\\5A=10\\A=2\\4A+5B=0\\B=-\frac{4A}{5}B=-\frac{8}{5}2C=1\\C=\frac{1}{2}\\So,\\y_{p}=2x+\frac{1}{2}e^{-x}-\frac{8}{5}---(3)\\$

The general solution is

$y=y_{h}+y_{p}$

from (2) ad (3)

$y=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))+2x+\frac{1}{2}e^{-x}-\frac{8}{5}$

6 0

3 years ago