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elena55 [62]
3 years ago
13

Find the domain of f(x) = Square 3 x + 8 ​

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
6 0

The question is a bit ambiguous: you may mean

\sqrt{3x+8}

or

\sqrt{3x}+8

Anyway, in both cases, the domain of a function involving a square root is found by imposing the content of the root to be greateer than or equal to zero. So, in the first case you have

3x+8\geq 0 \iff 3x\geq -8 \iff x\geq -\dfrac{8}{3}

In the second case, you have

3x\geq 0 \iff x\geq 0

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