Question

Find the domain of f(x) = Square 3 x + 8 ​

Answer 1

The question is a bit ambiguous: you may mean

$\sqrt{3x+8}$

or

$\sqrt{3x}+8$

Anyway, in both cases, the domain of a function involving a square root is found by imposing the content of the root to be greateer than or equal to zero. So, in the first case you have

$3x+8\geq 0 \iff 3x\geq -8 \iff x\geq -\dfrac{8}{3}$

In the second case, you have

$3x\geq 0 \iff x\geq 0$