9514 1404 393
Answer:
h ≤ 6 2/3
Step-by-step explanation:
The inequality is presumed to be ...
15h +40 ≤ 140
15h ≤ 100
h ≤ 6 2/3
__
The graph shows h ≥ 0, because the inequality is only reasonable for h ≥ 0.
The distance between any two points is:
d^2=(x2-x1)^2+(y2-y1)^2
d^2=(6--2)^2+(4--4)^2
d^2=8^2+8^2
d^2=64+64
d^2=128
d=√128 units
We have two solutions for this problem based on the given equation.
<u><em>Answer #1:</em></u>
<u>If the given equation was:</u>

To solve for f, we would need to isolate the "f" on one side of the equation.
In case of the above equation, we can simply do that by subtracting
from both sides of the equation
<u>This would give:</u>
f +
-
= 6 - 
f = 6 - 
<u><em>Answer #2:</em></u>
<u>If the given equation was:</u>

To solve for f, we would still need to isolate the "f" on one side of the equation.
<u>This can be done as follows:</u>
................> multiply both sides by (g)
f + 4 = 6g ................> subtract 4 from both sides of the equation
f + 4 - 4 = 6g - 4
f = 6g - 4
Hope this helps :)