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Furkat [3]
1 year ago
6

Find the slope -3/5 3/5 5/3 -5/3

Mathematics
1 answer:
Monica [59]1 year ago
8 0
The slope is y=-5/3x+2
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Robin was just hired at Groceries & More as a cashler. They pay her $12 an hour. She works 20 hours a week and is going to s
Lostsunrise [7]

Answer:

5 weeks

Step-by-step explanation:

We know that she works at a rate of $12 an hour, she also works 20 hours a week.

The total amount she makes per week is $240 (12 x 20). However, that is without deductions. We have to subtract $34 from the $240.

$240 - $34 = $206.

$206 is the amount she makes in a week and she wants to save $950. How many weeks does she have to save? Well, let's divide.

$950 / $206 = 4.6 weeks. However, if we have to round up to 5 weeks.

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1 year ago
A ball is thrown vertically upward.After t seconds its height(in feet)is given by the function h(t)=84t=16t^2.What is the maximu
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21 seconds!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
3 0
2 years ago
What is the decimal multiplier to increase by 99%? need it now
krek1111 [17]

Answer:

To work out the multiplier, first add or subtract the percentage from 100, then convert to a decimal. Example: we want to add 20% to £110. To work out the multiplier, add 20 to 100, to get 120, and then change it to a decimal (divide by 100) to get 1.2.

meiabatten191 helped me out on this question too.

3 0
2 years ago
Bowl A contains 6 apples and 3 mangoes this can be written as, Bowl B contain 8 apples and 2 mangoes this can be written as. Wha
Andrew [12]

Answer:

Bowl B contains 2 apples more than Bowl A and Bowl A contains 1 mango more than Bowl B.

Step-by-step explanation:

Number of apples in Bowl A = 6

Number of mangoes in Bowl B = 8

Difference in apples = 8 - 6 = 2

So, Bowl B contains 2 apples more than Bowl A.

Number of mangoes in Bowl A = 3

Number of mangoes in Bowl B =2

Difference in mangoes = 3 - 2 = 1

So, Bowl A contains 1 mango more than Bowl B.

3 0
2 years ago
PLEASE HELP ME!!!!!!!! 
Delicious77 [7]
Angle θ between two vectors is given by, \theta =cos^{-1}( \frac{u
 \cdot v}{|u||v|} ); where u \cdot 
v=-5(-4)+(-4)(-3)=20+12=32; |u|= \sqrt{ (-5)^{2} + (-4)^{2} } = 
\sqrt{25+16} = \sqrt{41} and |v|=\sqrt{ (-4)^{2} + (-3)^{2} } = 
\sqrt{16+9} = \sqrt{25}=5.
Therefore, \theta =cos^{-1}( \frac{32}{ 5\sqrt{41}} )=cos^{-1}0.9995=1.8^o
3 0
3 years ago
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