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Mandarinka [93]
3 years ago
12

If the median of the score distribution on this pop quiz is more than 170, the teacher will drop the next pop quiz. The pop quiz

scores followed this distribution: {180, 175, 163, 186, 153, 194, 198, 183, 187, 174, 177, 196, 162, 185, 174, 195, 164, 152, 144, 138, 125, 110}. What is the median of the distribution? 168.86 170.78 183.23 174.50 180.56
Mathematics
1 answer:
irakobra [83]3 years ago
7 0
Arr arrange the 22  scores in ascending order. The median will be the 'middle'  2 scores which is the mean of the 11th and 12th score.

The middle 2  scores are 174 and 175 so the median = 174.50.
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PLS PLS HELP, I DONT WANT TO FAIL!!
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Answer:

2.0 seconds

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<u>Given quadratic functions</u>:

\begin{cases}y=-7x^2+26x+3\\y=-6x^2 +23x+5\end{cases}

To find the time, in seconds, that the balloons collided at the highest point, <u>substitute</u> one equation into the other equation and rearrange to <u>equal zero</u>:

\begin{aligned}-6x^2+23x+5 & = -7x^2+26x+3\\-6x^2+23x+5+7x^2 & = -7x^2+26x+3+7x^2\\x^2+23x+5 & = 26x+3\\x^2+23x+5-26x & = 26x+3-26x\\x^2-3x+5& = 3\\x^2-3x+5-3& = 3-3\\x^2-3x+2& = 0\end{aligned}

<u>Factor</u> the quadratic:

\begin{aligned}x^2-3x+2 & = 0\\x^2-2x-x+2 & = 0\\x(x-2)-1(x-2) & = 0\\(x-1)(x-2) & = 0\\\end{aligned}

Apply the <u>zero-product property</u> to solve for x:

\implies (x-1)=0 \implies x=1

\implies (x-2)=0 \implies x=2

Therefore, the balloons collided at 1 second and 2 seconds.  

To find at which time the highest point of collision occured, substitute both values of x into one of the functions:

f(1)=-6(1)^2 +23(1)+5=22

f(2)=-6(2)^2 +23(2)+5=27

Therefore, the time, in seconds, that the balloons collided at the highest point is 2.0 seconds.

Learn more about quadratic systems of equations here:

brainly.com/question/27930827

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I'm just eyeballing the chart but imma guess .9
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