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ipn [44]
4 years ago
13

Andrea can clean a house 4 times as fast as Denise. When they work together, Andrea and Denise can clean a large house in 8 hour

s. How many hours would it take Denise to clean the house by herself?
20
15
40
5
Mathematics
2 answers:
steposvetlana [31]4 years ago
8 0

Answer:

8 hours

Step-by-step explanation:

A&D can clean a house in 8 hours together.

 

 

Proportionally, Denise works at x.  Andrea works at 4x.  There is a total of 5x.

 

Out of the 5x, Denise accounts for x.

 

x/5x = 1/5 of the work over 8 hours.

 

1/5 ( Denise's time for cleaning the whole house) = 8 hours.

 

Multiply both sides by 5:

 

5(1/5)(Denise's time for cleaning the whole house) = 5*8

 

Denise's time for cleaning the whole house = 40 hours

 

 

I like this method better...

 

 

That means in ONE hour, they get 1/8 of the job done.

 

Let's say Denise takes x hours to clean the house.

In one hour, she would do 1/x of the job (x can't be 0 hours).

 

Since Andrea does the house 4 times as fast as Denise, who takes x hours to do the job,  Andrea takes x/4 hours.

 

In one hour, Andrea does 4/x of the job.

 

In one hour the part of the job Andrea does, plus the part of the job Denise does, must total 1/8.

 

(4/x) + (1/x) = 1/8

 

5/x = 1/8

 

Cross multiply:

x = 40

 

So it would take Denise 40 hours to clean the house by herself.  (She's not really that efficient, or the house was REALLY dirty.

 

Andrea takes x/4 hours or 40/4 = 10 hours to clean the house by herself.

 

So with a little help from Denise, Andrea decreases her time to clean the house from the 10 hours it would take by herself to 8 hours.

Mashutka [201]4 years ago
7 0
Hmmm

a=amount of house andrea can clean in 1 hour
d=amount of house denise can clean in 1 hour

8a+8d=1house
and
andrea can clean 4 times faster
that means in 1 hour, andrea cleans 4 times of denise
so
a=4d
sub back

8a+8d=1 house
8(4d)+8d=1 house
32d+8d=1 house
40d=1 house

takes her 40 hours

answer is 40 hours
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