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3 years ago

Which will reduce the possible environmental damage associated with mining uranium?

Chemistry

2 answers:

blagie [28]3 years ago

7 0

We need to discuss about reduction of possible environmental damage associated with uranium mining.

There are several extraction processes involved in mining uranium as- (i) surface mining, (ii) heap leaching, (iii) underground mining and so on.

There are so many risks involved towards environment and health.

There are some improvements for long term stabilization of Uranium mining have been documented. They are as follows-back-filling and using residues for the construction of motorways, washing of soil with water, carbon treatment inclusion of new materials like room temperature ceramics for the immobilization of various contaminants, de-watering, and land encapsulation.

Sergeu [11.5K]3 years ago

3 0

Answer:

B. increasing the reprocessing of used fuel for reuse

Explanation:

I took the test.

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What would form a solution?

Ipatiy [6.2K]

Answer:

B. Mixing a solute and a solvent

Explanation:

Hello,

In this case, solutions are defined as liquid homogeneous mixtures formed when two substances having affinity are mixed. It is important to notice that the two substances are known as solute, which is added to other substance that is the solvent. Therefore, answer is B. Mixing a solute and a solvent.

Notice that when two insoluble substances are mixed no solution is formed. Furthermore, if two solutes together or a solute and a precipitate are mixed, no liquid homogeneous solution is formed, as commonly solutes are solid, nevertheless, when liquid, one should have to act as the solvent.

Best regards.

6 0

4 years ago

given a k value of 0.43 for the following aqueous equilibrium suppose sample z is placed into water such that its original conce

serious [3.7K]

Answer:

Less than 0.033 M:

$[Z]_{eq}=2.4x10^{-3}M$

Explanation:

Hello,

In this case, the described equilibrium is:

$2A+B\rightarrow 2Z$

Thus, the law of mass action is:

$K=\frac{[Z]^2}{[A]^2[B]}=0.43$

Nevertheless, given the initial concentration of Z that is 0.033 M, we should invert the equilibrium since the reaction will move leftwards:

$\frac{1}{K}=\frac{[A]^2[B]}{[Z]^2}=\frac{1}{0.43}=2.33$

Know, by introducing the change $x$ due to the reaction extent, we can write:

$2.33=\frac{(2x)^2*x}{(0.033-2x)^2}$

Which has the following solution:

$x_1=2.29M\\x_2=0.0181M\\x_3=0.0153M$

But the correct solution is $x_3=0.0152M$ since the other solutions make the equilibrium concentration of Z negative which is not possible. In such a way, its concentration at equilibrium is:

$[Z]_{eq}=0.033M-2(0.0153M)$

$[Z]_{eq}=2.4x10^{-3}M$

Which is clearly less than 0.033 M since the addition of a product shift the reaction leftwards in order to reestablish equilibrium (Le Chatelier's principle).

Regards.

6 0

3 years ago

Which of the following is the same as 1 second?

Soloha48 [4]

It’s 5 When u do 1k which is 1000 it’s equal to 0.1 then = 100 which then u do 95 coz that’s a lucky number and u get 5

8 0

3 years ago

Determine the empirical formula of a compound containing 30.4%N and 69.6%O

pochemuha

30.4 is the answer

<span> composition is: 58.8 0/0 C, 9.9 0/0 H, and 31.3 0/0 </span>O<span>. Ifit's molecular mass is 306 ... composition of the </span>compound<span> is </span>30.4<span>% </span>

6 0

4 years ago

Which part of thr drug discovery life cycle can quantum computung impact the most

Charra [1.4K]

Molecular simulation is the part of the drug discovery life cycle that most likely uses quantum computing.

<h3>What is drug discovery?</h3>

Drug discovery refers to the process to identify and validate medications in pharmaceutical research.

Drug discovery exploits computational approaches based on quantum modeling to accelerate this process.

In conclusion, molecular simulation is the part of drug discovery associated with quantum computing.

Learn more about drug discovery here:

brainly.com/question/14330435

#SPJ1

6 0

2 years ago