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Anon25 [30]
3 years ago
7

Classify the type of this chemical reaction: C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)

Chemistry
2 answers:
sweet-ann [11.9K]3 years ago
8 0
The given reaction is a combustion reaction, since a hydrocarbon is burning in presence of oxygen
Arlecino [84]3 years ago
8 0

Explanation:

A chemical reaction in which a hydrocarbon reacts with oxygen atom and results in the formation of carbon dioxide and water is known as combustion reaction.

For example, C_{3}H_{8}(g) + 5O_{2}(g) \rightarrow 3CO_{2}(g) + 4H_{2}O(g)

Here, propane is the hydrocarbon which is reacting with oxygen atom and yields carbon dioxide and water.

Therefore, we can conclude that the given chemical reaction is a combustion reaction.

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Answer:N

Explanation:

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3 years ago
If 11.0 g of ccl3f is enclosed in a 1.1 −l container, will any liquid be present?if so, what mass of liquid?
Anastasy [175]
Considering that CCL3F gas behave like an ideal gas then we can use the Ideal Gas Law 
<span>PV = nRT, however is an approximation and not the only way to resolve this problem with the given data..So,at the end of the solution I am posting some sources for further understanding and a expanded point of view. </span>

<span>Data: P= 856torr, T = 300K, V= 1.1L, R = 62.36 L Torr / KMol </span>

<span>Solving and substituting in the Gas equation for n = PV / RT = (856)(1.1L) /( 62.36)(300) = 0.05 Mol. This RESULT is of any gas. To tie it up to our gas we need to look for its molecular weight:MW of CCL3F = 137.7 gm/mol.  </span>

<span>Then : 0.05x 137.5 = 6.88gm of vapor </span>

<span>If we sustract the vapor weight from the TOTAL weight of liquid we have: 11.5gm - 6.88gm = 4.62 gm of liquid.d</span>
8 0
3 years ago
How many grams is .15mol of argon
bonufazy [111]

Answer:

The answer is 39.948.

Explanation:

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3 years ago
What are the treatments for Down syndrome
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5 0
4 years ago
Cars run on gasoline, where octane (C8H18) is the principle component. This combustion reaction is responsible for generating en
Bezzdna [24]

Answer:

  • 10.19 g CO₂
  • 4.69 g H₂O

Explanation:

The combustion reaction of Octane is:

  • C₈H₁₈ → 8CO₂ + 9H₂O

To calculate the mass of CO₂ and H₂O produced, we need to know the mass of octane combusted.

We calculate the mass of Octane from the given volume and density, using the following <em>conversion factors</em>:

  • 1 gallon = 3.785 L
  • 1 L = 1000 mL

Now we<u> convert 1.24 gallons to mL</u>:

  • 1.24 gallon * \frac{3.785L}{1gallon} *\frac{1000mL}{1L} = 4693.4 mL

We <u>calculate the mass of Octane</u>:

  • 4693.4 mL * 0.703 g/mL = 3.30 g Octane

Now we use the <em>stoichiometric ratios</em> and <em>molecular weights</em> to <u>calculate the mass of CO₂ and H₂O</u>:

  • CO₂ ⇒ 3.30 g Octane ÷ 114g/mol * \frac{8molCO_{2}}{1molOctane} * 44 g/mol =  10.19 g CO₂
  • H₂O ⇒ 3.30 g Octane ÷ 114g/mol * \frac{9molH_{2}O}{1molOctane} * 18 g/mol = 4.69 g H₂O

7 0
4 years ago
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