The specific heat capacity of water is 4200J/(kg*℃). So when absorbs 209 joules, the water sample will increase 209/(4200*0.01)=5℃. So the final temperature of sample is 23+5=28℃.
The. Answer is number seven
Basically they are asking you to find the element that is most closely associated with these clues.
1. Fireworkium: 15 protons and 15 electrons? No problem. We can see that the atomic number is 15, in which in real life, the element is Phosphorous. (Phosphorous is a common element in fireworks for an explosive personality and colors)
2. Toothium: A nonmetal with average mass number close to 19? We check the periodic table once more and find that Fluorine is our answer. (Notice that fluorine is in toothpaste, which is why they decided the name Toothier)
3. Breathium: Now honestly, I didn't even have to check the periodic table but just realize that we breath Oxygen. But if you want the straight answer, Oxygen is a nonmetal which has an atomic mass close to 16, and surprise, it has one less proton than Fluorine.
4.Lightium: Immediately we see that since this gas does not react with other elements, it is a noble gas. If it glows in a lamp or vacuum tube, we can also see it is of a light origin. If it has one more proton than Toothium (Fluorine) than we can immediately see that in the periodic table, our answer is Neon.
5. Rottoneggium: We can immediately guess sulfur. The straight way shows that it has 16 electrons, and the non-ion atom should also have 16 protons. Therefore, our answer is Sulfur.
6. I just realized I forgot Floatium: If it has 2 protons, we look in the periodic table and see that our answer is Helium.
Sometimes true depending on your problem
Answer:
92.4 grams.
Explanation:
- From the balanced reaction:
<em>CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O,</em>
1.0 mole of CaCO₃ reacts with 2.0 moles of HCl to produce 1.0 mole of CaCl₂, 1.0 mole of CO₂, and 1.0 mole of H₂O.
- We need to calculate the no. of moles of (104 g) of CaCO₃:
<em>no. of moles of CaCO₃ = mass/molar mass</em> = (104 g)/(100.08 g/mol) = <em>1.039 mol.</em>
<u><em>Using cross multiplication:</em></u>
1.0 mole of CaCO₃ produce → 1.0 mole of CaCl₂.
∴ 1.039 mole of CaCO₃ produce → 1.039 mole of CaCl₂.
∴ The amount of CaCl₂ produced = no. of moles x molar mass = (1.039 mol)(110.98 g/mol) = 114.3 g.
∵ percent yield of the reaction = [(actual yield)/(theoretical yield)] x 100.
Percent yield of the reaction = 80.15%, theoretical yield = 115.3 g.
<em>∴ actual yield = [(percent yield of the reaction)(theoretical yield)]/100 </em>= [(80.15%)/(115.3 g)] / 100 = <em>92.42 g ≅ 92.4 g.</em>
