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Cloud [144]
3 years ago
6

A rectangular pool is twice as

Mathematics
2 answers:
dedylja [7]3 years ago
8 0

Step-by-step explanation:

L=2B

P=2(L+B)

48=2(2B+B)

48=2(3B)

48=6B

B=8yd

L=2*8

=16yd

velikii [3]3 years ago
6 0

Answer:

length * width = 16 yd * 8 yd

or

length = 16 yd

width = 8 yd

Step-by-step explanation:

take the rectangular pool to have sides a (length) and 2a (width).

we are told that the length is as twice as its width, therefore,

Perimeter is given by (a + 2a) × 2 = 48 yd

Divide both sides by 2 ⇒ \frac{((a + 2a) * 2)}{2} = \frac{48 yd}{2} ⇒ a + 2a = 24 yd

⇒3a = 24 yd

Divide both sides by 3 ⇒ \frac{3a}{3} = \frac{24 yd}{3} ⇒ a = 8 yd

therefore, the width of the pool is 8 yd and its length is 16 yd (Twice as long as it is wide)

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xz_007 [3.2K]

To add or sum this arrary, beg ∈ {array} {r} 37 \202\ + 160/ ∈  end {array} gives <u>A) 399</u>.

<h3>What is an array?</h3>

An array is a data structure made up of some elements.

The sum of all elements in an array is found by adding up the elements in the array.

<h3>Data and Calculations:</h3>

Elements of the array = 37, 202, and 160

The sum of the array, 37 + 202 + 160 = 399

Thus, to add or sum this arrary, beg ∈ {array} {r} 37 \202\ + 160/ ∈  end {array} gives <u>A) 399</u>.

Learn more about arrays at brainly.com/question/23698059

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<h3>Question:</h3>

Add beg ∈ {array} {r} 37 \202\ + 160/ ∈  end {array}

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A) 399

B) 389

C) 400

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Step-by-step explanation:

Hope this helped :)

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