When a set of reflections that carry a shape onto itself, it means that the final position of the shape will be the same as its original location

Reflections (a) y=x, x-axis, y=x, y-axis would carry the hexagon onto itself

First; we test the given options, until we get the true option

(a) y=x, x-axis, y=x, y-axis

The rule of reflection y =x is:

$(x,y) \to (y,x)$

The rule of reflection across the x-axis is:

$(x,y) \to (x,-y)$

So, we have:

$(y,x) \to (y,-x)$

The rule of reflection y =x is:

$(x,y) \to (y,x)$

So, we have:

$(y,-x) \to (-x,y)$

Lastly, the reflection across the y-axis is:

$(x,y) \to (-x,y)$

So, we have:

$(-x,y) \to (x,y)$

So, the overall transformation is:

$(x,y) \to (x,y)$

Notice that, the original and final coordinates are the same.

This means that:

Reflections (a) y=x, x-axis, y=x, y-axis would carry the hexagon onto itself

Read more about reflections at:

brainly.com/question/938117

4 0

2 years ago

How do I do this? 4/5x>14

Likurg_2 [28]

Well, first, you need to know what you want to 'do' to it.

You want to find the description of what 'x' has to be in order to
make that inequality a true statement. Here's one way to do it:

      4/5 x > 14

Multiply each side by 5 :   4    x > 70

Divide each side by 4 :    x > 17.5 .

That's it. As long as 'x' is more than 17.5 ,
the original inequality is true.

3 0

3 years ago