Simplify 5(x - 6). -x 5x - 6 5x

Feliz [49]

Answer:

15

Step-by-step explanation:

there are 15 sixteenths in 15/16, how you figure this out is the numerator tells you how many are in the fraction, in this case the numerator says 15, so there are 15, sixteenths in, 15/16

8 0

3 years ago

Work out the height of a parallelogram with base of 6cm and area of 27cm²

professor190 [17]

To find the height of the parallelogram you would divide 6 from the area, 27, to get the answer 4.5,
So h=4.5

5 0

3 years ago

Help! i need the answer to this question plsss NO LINKS AND NO DOING IT JUST FOR THE POINTS Will give brainliest to the first se

Alex_Xolod [135]

2745

Step-by-step explanation:

solve it like simultaneously

180x+120y greater than 5145

180x+120y greater than 2400

eliminate x

y will now be greater than 2745

5 0

3 years ago

Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat

drek231 [11]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$

And $P(X_i) \geq 0, \forall x_i$

So then we have a probability distribution

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

6 0

3 years ago

Find the value of X in each of the given triangles.

ki77a [65]

<DSR + <SRD + <RDS = 180° (Angle sum property)

2x + x +3x = 180°

6x = 180°

x = 180°/6

x = 30°

So, <SRD = x = 30°

<RDS = 3x = 3(30°) =90°

<DSR = 2x = 2(30°) = 60°

Hope it helps !

✌️

Jai hind !

8 0

3 years ago

Read 2 more answers

Simplify 5(x - 6). -x 5x - 6 5x - 30