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Fynjy0 [20]
3 years ago
10

Solve this equation. 2/3x−1/5x=x−1

Mathematics
2 answers:
sergejj [24]3 years ago
7 0

Answer:

1,875

Step-by-step explanation:

\frac{2}{3}x-\frac{1}{5}x=x-1\\\\=> \frac{2.5}{15}x-\frac{3}{15}x=x-1    \\\\=> \frac{2.5-3}{15}x=x-1\\\\=> \frac{10-3}{15}x=x-1\\\\\frac{7}{15}x=x-1\\\\=> 7 x=15(x-1)\\\\ 7x=15x-15\\\\ 8x=15\\\\ x =\frac{15}{8}=1,875

KonstantinChe [14]3 years ago
6 0

Answer:

 =  1  7/8

Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

6 0
4 years ago
If ORBIT is coded BEOVG, then how is PLANET coded? /
arlik [135]

Answer:

1. CYNARG

Step-by-step explanation:

This a example of Caesar's Cipher, in which each letter in the original word leads to a ciphered letter according to the following equation:

C = (P + o) \text{mod} 26

In which C is the index of the Ciphered letter in the alphabet, P is the index of the original letter and o is the offset.

Finding the offset:

O is coded B

O is the 15th letter in the alphabet, so P = 15.

B is the 2nd letter in the alphabet, so C = 2

C = (P + o) \text{mod} 26

2 = (15 + o) \text{mod} 26

|o = |2-15| \text{mod} 26

o = 13

So

C = (P + 13) \text{mod} 26

PLANET:

P

P is the 16th letter in the alphabet.

C = (16 + 13) \text{mod} 26 = 3

So P is coded C.

L

L is the 12th letter in the alphabet:

C = (12 + 13) \text{mod} 26 = 25

L is coded Y(25th letter in the alphabet)

A

A is the 1st letter in the alphabet

C = (1 + 13) \text{mod} 26 = 14

A is coded N

N

N is the 14th letter in the alphabet

C = (14 + 13) \text{mod} 26 = 1

N is coded A

E

E is the 5th letter in the alphabet

C = (5 + 13) \text{mod} 26 = 18

E is coded R

So the correct answer is:

1. CYNARG

4 0
3 years ago
There are several sets of different numbers which can be chosen from {0,1,2,3,4,5,6,7,8,9}. How many of these sets contain any 2
Leokris [45]

Answer:

90

Step-by-step explanation:

it is 90 because in the first slot there can be any 10 numbers and in the second slot the set can contain any of the remaining 9 numbers and then we can multiply these two numbers together to find the total amount of sets.

hope this helps :)

4 0
3 years ago
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