1. 9/15 and 10/15
2. 7/9 and 6/9
3. 16/24 and 3/24
4. 3/12 and 8/12
5. 25/30 and 18/30
Replace X with 3 and simplify. The answer you would get is 11.
We want to see how many solutions has an equation given some restrictions on the vectors of the equation.
We have 3 vectors in R2.
v₁, v₂, and v₃.
Where we know that v₁ and v₂ are parallel. And two vectors are parallel if one is a scalar times the other.
Then we can write:
v₂ = c*v₁
Where c is a real number.
Then our system:
x*v₁ + y*v₂ = v₃
Can be rewriten to:
x*v₁ + y*c*v₁ = v₃
(x + y*c)*v₁ = v₃
Assuming x, y, and c are real numbers, this only has a solution if v₁ is also parallel to v₃, because as you can see, the equation says that v₃ is a scallar times v₁.
Geometrically, this means that if we sum two parallel vectors, we will get a vector that is parallel to the two that we added.
If you want to learn more, you can read:
brainly.com/question/13322477
Answer:
? = 3
Step-by-step explanation:
To find the value of ?, substitute one of the ordered pairs from the table [except (0, 0)] into the given formula and solve for ?.
Given formula:
Substitute x = 1 and y = 3 into the formula:
To isolate ? divide both sides by 1:
Therefore, ? = 3:
Check by inputting another value of x from the table into the found formula and comparing the calculated y-value:
Answer:
factors-----(a+2)(a^2+4-3a)
