C because since this is a incomplete equation, finding the missing area all you have to do is divide
Please, share just ONE problem at a time. Thanks.
<span>Solve 2x^2-12x+20=0:
Simplify this by dividing each term by 2: x^2 - 6x + 10 = 0
Identify a, b and c: a=1, b=-6 and c=10. Then b^2=36.
Write out the solutions using the quadratic formula:
6 plus or minus sqrt(36-40)
x = ---------------------------------------
2
sqrt(36-40) = sqrt(-4) = plus or minus i2
Then:
6 plus or minus i2
x = --------------------------- (answer)
2</span>
Answer:
88 m^2
Step-by-step explanation:
They're simply trying to confuse you with the rest of the numbers.
7+4 = 11
^To get the base length.
8 is the height.
11*8=88.
Use the power, product, and chain rules:

• product rule

• power rule for the first term, and power/chain rules for the second term:

• power rule

Now simplify.

You could also use logarithmic differentiation, which involves taking logarithms of both sides and differentiating with the chain rule.
On the right side, the logarithm of a product can be expanded as a sum of logarithms. Then use other properties of logarithms to simplify

Differentiate both sides and you end up with the same derivative:

Answer:
4 5/12
Step-by-step explanation:
Convert to mixed fraction 7/4 + 8/3
Find common denominator, 12
21/12 + 32/12
add numerators (21+32)/12 = 53/12
reduce fraction 4 5/12