If ADAB ACBA, ZD = 132° and ZC = x + 18
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Let's do
Release k for some while
If
- we take h=0
So
- y=3/x
So vertical asymptote is at origin now
It mentioned that it's at x=-5 so we need to change x
- put -5 in place of h
- Vertical asymptote at x=-5
Now
- for k=0 horizontal asymptote at origin
But it's given
- y is at 12
Same put y=12 in place of k
- h=-5
- k=12
Graph attached for verification
The range of sin x 
Thus range of 2sin x =
= 
Thus range of 2sin x =