Find the value of each variable.

Below are the scatter plot and residual plot for a set of data.

Vsevolod [243]

Answer:

A linear model (is/is not) the best fit for the data because the residual plot (shows no pattern/shows a pattern) and is (scattered/not scattered).

Step-by-step explanation:

A linear model should be used when you want to view the data as a continuous response. This means that when the data is increasing/describing then the line should be in a uniform pattern.

If you were to look at the residual plot, you can see that the points curve in a pattern, meaning that the point is not scattered which is not good criteria for a residual plot.

Mentioned before, the points on the residual plot are in a pattern, so it’s not scattered as well.

4 0

3 years ago

What is the quotient?

Iteru [2.4K]

Answer:

A

Step-by-step explanation:

this is a fraction we two powers with the same base so we have tu subtract the exponents and maintain the same base

5^(-6-3) = 5^-9 = 1/5^9

8 0

3 years ago

Read 2 more answers

Why can a problem with extra information be difficult to solve?

Semenov [28]

I think it is more difficult because it is more for your brain to have to process at once .

7 0

3 years ago

Find the nth term of the sequence 7,25,51,85,127

olya-2409 [2.1K]

Let a (n) denote the n-th term of the given sequence.

Check the forward differences, and denote the n-th difference by b (n). That is,

b (n) = a (n + 1) - a (n)

These so-called first differences are

b (1) = a (2) - a (1) = 25 - 7 = 18

b (2) = a (3) - a (2) = 51 - 25 = 26

b (3) = a (4) - a (3) = 85 - 51 = 34

b (4) = a (5) - a (4) = 127 - 85 = 42

Now consider this sequence of differences,

18, 26, 34, 42, …

and notice that the difference between consecutive terms in this sequence b is 8:

26 - 18 = 8

34 - 26 = 8

42 - 34 = 8

and so on. This means b is an arithmetic sequence, and in particular follows the rule

b (n) = 18 + 8 (n - 1) = 8n + 10

for n ≥ 1.

So we have

a (n + 1) - a (n) = 8n + 10

or, replacing n + 1 with n,

a (n) = a (n - 1) + 8 (n - 1) + 10

a (n) = a (n - 1) + 8n + 2

We can solve for a (n) by iteratively substituting:

a (n) = [a (n - 2) + 8 (n - 1) + 2] + 8n + 2

a (n) = a (n - 2) + 8 (n + (n - 1)) + 2×2

a (n) = [a (n - 3) + 8 (n - 2) + 2] + 8 (n + (n - 1)) + 2×2

a (n) = a (n - 3) + 8 (n + (n - 1) + (n - 2)) + 3×2

and so on. The pattern should be clear; we end up with

a (n) = a (1) + 8 (n + (n - 1) + … + 3 + 2) + (n - 1)×2

The middle group is the sum,

$\displaystyle 8\sum_{k=2}^nk=8\sum_{k=1}^nk-8=\frac{8n(n+1)}2-8=4n^2+4n-8$

so that

a (n) = a (1) + (4n ² + 4n - 8) + 2 (n - 1)

a (n) = 4n ² + 6n - 3

4 0

3 years ago

Who was the first person to find out pi (3.14)

goldfiish [28.3K]

The first person who calculated pi was Archimedes got really close however with the mathematics he had in his time he did not have decimal points nor could he use the number 0. So it has to latter once people recognize 0 as a number and the decimal point that we get what we have today.

3 0

4 years ago