Answer:
There are two options: b) 
, c) 
.
Step-by-step explanation:
By Trigonometry, we know that function tangent is equal to the following identity in terms of functions sine and cosine:
(1)
If we know that 
and 
, then 
. Hence, we have two possibilities: b) , c) .
I feel like the answer Would be C but I could be wronge
A trig identity is <span>asinucosu=<span>a/2</span>sin(2u)</span>So you can write your equation as<span>y=sin(x)cos(x)=<span>1/2</span>sin(2x)</span>Use the crain rule here<span><span>y′</span>=<span>d/<span>dx</span></span><span>1/2</span>sin(2x)=<span>1/2</span>cos(2x)<span>d/<span>dx</span></span>2x=cos(2x)</span>The curve will have horizontal tangents when y' = 0.<span><span>y′</span>=0=cos(2x)</span>On the interval [-pi, pi], solution to that is<span><span>x=±<span>π4</span>,±<span><span>3π</span>4</span></span></span>
