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3 years ago

13

A human heart beats an average of 80 beats per minute. How many heart beats is this in a day

1 answer:

vovangra [49]3 years ago

3 0

Answer:

115200

Step-by-step explanation:

80 Beats Per Minute <em><u>x</u></em> 60 Minutes (1 hour) <em><u>x</u></em> 24 Hours (1 Day) = 115200

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The grandma of a 6-year-old is asking them 2x3 what is 2x3

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Answer:

The answer of 2 x 3 would be 6

Step-by-step explanation:

The reason why 2 x 3 or 2 times 3 would be six/6. Is because if you had 2 pairs of 3 items, you would get a total of 6 items. And if you had 3 pairs of 2 items, you would still have a total of 6 items.

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Alex drove 135 miles in 3 hours at a constant speed

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What is the derivative of this

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$\bf r(x)=\cfrac{3x-2}{2x+5}\implies \cfrac{dr}{dx}=\stackrel{quotient~rule}{\cfrac{3(2x+5)~~-~~(3x-2)2}{(2x+5)^2}}
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3 years ago

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3 years ago

Read 2 more answers

Do you agree with the statement that " cubic functions must have at least 1 x-intercept but not more than 3, whereas quadratic f

vladimir2022 [97]

Answer:

Yes, I agree

Step-by-step explanation:

For the cubic function

A cubic function is represented as:

$f(x)=ax^3+bx^2+cx+d$

A cubic function may have 1, 2 or 3 x intercepts. This is shown below

For 3 x intercepts

$y = x^3 - x$

Equate y to 0

$x^3 - x = 0$

Expand

$x(x^2 - 1) = 0$

Express $x^2 - 1$ as difference of two squares

$x(x - 1)(x +1 ) = 0$

<em>x = 0 or 1 or -1</em>

For 2 x intercepts

$y = x^3 - x$

$y =(x-5)^2)(x+7)$

Equate y to 0

$(x-5)^2(x+7) = 0$

Expand

$(x-5)(x-5)(x+7) = 0$

<em>x= 5 or x = -7</em>

For 1 x intercept

$y = x^3$

Equate y to 0

$x^3 = 0$

Take cube roots of both sides

$x = 0$

It has been shown above that a cubic function may have 1, 2 or 3.

So, I agree to the statement

For the quadratic function

A quadratic function will not have any x intercept when the function can not be factorized;

E.g.

$y = x^2 + x + 17$

<em>The above function has no x intercept.</em>

A quadratic function will have at least 1 x intercept when the function can be factorized;

E.g.

$y = x^2- 6x + 9$

Equate y to 0

$x^2- 6x + 9 = 0$

Expand

$x^2 - 3x - 3x + 9 = 0$

$(x - 3)(x-3) = 0$

$x = 3$

We've shown that a quadratic may have no x intercept, and it may also have x intercept(s)

Hence, I agree to both statement

3 0

2 years ago