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Katena32 [7]
3 years ago
7

What is the derivative of this

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
7 0
\bf r(x)=\cfrac{3x-2}{2x+5}\implies \cfrac{dr}{dx}=\stackrel{quotient~rule}{\cfrac{3(2x+5)~~-~~(3x-2)2}{(2x+5)^2}}
\\\\\\
\cfrac{dr}{dx}=\cfrac{\underline{6x}+15\underline{-6x}+4}{(2x+5)^2}\implies \cfrac{dr}{dx}=\cfrac{19}{(2x+5)^2}
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What is the shape of -2x^(2)+6y^(2)+5x+5y-4=0
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Answer:

Step-by-step explanation:

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|6m-54|, if m<9 help rsm
bija089 [108]

Answer:

|6m - 54|   \: >  \: 0

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Let

y =  |6m - 54|

We can factor 6 to get:

y = 6 |m - 9|

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What is the area of the figure?<br> Enter your answer in the box.
lukranit [14]
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An open metal tank of square base has a volume of 123 m^3
snow_lady [41]

Answer:

  a) h = 123/x^2

  b) S = x^2 +492/x

  c) x ≈ 6.27

  d) S'' = 6; area is a minimum (Y)

  e) Amin ≈ 117.78 m²

Step-by-step explanation:

a) The volume is given by ...

  V = Bh

where B is the area of the base, x^2, and h is the height. Filling in the given volume, and solving for the height, we get:

  123 = x^2·h

  h = 123/x^2

__

b) The surface area is the sum of the area of the base (x^2) and the lateral area, which is the product of the height and the perimeter of the base.

S=x^2+Ph=x^2+(4x)\dfrac{123}{x^2}\\\\S=x^2+\dfrac{492}{x}

__

c) The derivative of the area with respect to x is ...

S'=2x-\dfrac{492}{x^2}

When this is zero, area is at an extreme.

0=2x -\dfrac{492}{x^2}\\\\0=x^3-246\\\\x=\sqrt[3]{246}\approx 6.26583

__

d) The second derivative is ...

S''=2+\dfrac{2\cdot 492}{x^3}=2+\dfrac{2\cdot 492}{246}=6

This is positive, so the value of x found represents a minimum of the area function.

__

e) The minimum area is ...

S=x^2+\dfrac{2\cdot 246}{x}=(246^{\frac{1}{3}})^2+2\dfrac{246}{246^{\frac{1}{3}}}=3\cdot 246^{\frac{2}{3}}\approx 117.78

The minimum area of metal used is about 117.78 m².

3 0
2 years ago
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