You can notice that each term of the sequence has a denominator with powers of 2. The first term has 2 powered to 0, the second term has a 2 powered to 1 and so on. The numerator is always 3.
Then, for the n-th term, you have:
What is the solution-|-x|=-12
1 answer:
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Answer:
If order matters: 2,594,592,000 ways.
If order does not matter: 64,350 ways
Step-by-step explanation:
Assuming that the order matters when picking the non-pitching positions (since they are different positions), the number of possible different starting lineups is given by the permutation of picking 8 players out of 15, multiplied by 10 (pick one out of 10 pitchers):
Now if the order of the field players is not important, the number of possible starting lineups is given by the combination of picking 8 players out 15, multiplied by 10:
Therefore, the number of ways to pick the starting lineup is:
If order matters: 2,594,592,000 ways.
If order does not matter: 64,350 ways