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stich3 [128]
4 years ago
15

Write a net ionic equation to show that acetylsalicylic acid (aspirin), hc9h7o4, behaves as a brønsted-lowry acid in water.

Chemistry
2 answers:
scoray [572]4 years ago
5 0

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory:

  1. An acid is defined as a substance which looses donates protons and thus forming conjugate base.
  2. A base is defined as a substance which accepts protons and thus forming conjugate acid.

Acetylsalicylic acid when dissolved in water donates its proton to form conjugate base and water gains the proton to form conjugate acid.The net ionic equation is given as:

HC_9H_7O_4(0+H_2O\rightarrow (C_9H_7O_4)^{-}+H_3O^+

nadya68 [22]4 years ago
4 0
Balanced chemical reaction of aspirin in water:
HC₉H₇O₄(aq) + H₂O(l) ⇄ C₉H₇O₄⁻(aq) + H₃O⁺(aq).
In this chemical reaction aspirin(HC₉H₇O₄) is an acid because it donates a proton (H⁺) to water and becomes its conjugate base (C₉H₇O₄⁻) and water is a base because it accepts a proton from aspirin<span> and becomes its conjugate acid, the </span>hydronium<span> ion, (H</span>₃O⁺).
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A student measures out exactly 0.105 g of salicylic acid and runs the experiment as dictated in the lab manual. They obtain 0.11
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<u>Answer:</u> The percent yield of the reaction is 8.10 %.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

Given mass of salicylic acid = 0.105g

Molar mass of salicylic acid = 138.12 g/mol

Putting values in equation 1, we get:

\text{Moles of salicylic acid}=\frac{0.105g}{138.12g/mol}=0.0079mol

The chemical equation for the formation of aspirin from salicylic acid follows:

\text{Salicylic acid + Acetic anhydride}\rightarrow \text{Aspirin + Acetic acid}

By Stoichiometry of the reaction:

1 mole of salicylic acid produces 1 mole of aspirin

So, 0.0076 moles of salicylic acid will produce = \frac{1}{1}\times 0.0076=0.0076mol of aspirin

Now, calculating the mass of aspirin from equation 1, we get:

Molar mass of aspirin = 180.16 g/mol

Moles of aspirin = 0.0076 moles

Putting values in equation 1, we get:

0.0076mol=\frac{\text{Mass of aspirin}}{180.16g/mol}\\\\\text{Mass of aspirin}=(0.0076mol\times 180.16g/mol)=1.37g

To calculate the percentage yield of aspirin, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of aspirin = 0.111 g

Theoretical yield of aspirin = 1.37 g

Putting values in above equation, we get:

\%\text{ yield of aspirin}=\frac{0.111g}{1.37g}\times 100\\\\\% \text{yield of aspirin}=8.10\%

Hence, the percent yield of the reaction is 8.10 %.

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