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zhuklara [117]
3 years ago
7

A large box of disposable diapers contains 150 diapers. Baby Bianca used 9 boxes during her first year and 7 boxes during her se

cond year. If the average baby uses 4,500 diapers by age 2, how many fewer diapers did Bianca use than the average baby
A. 3,150 fewer diapers B. 2,400 fewer diapers
C. 2,100 fewer diapers D. 2,200 fewer diapers
Mathematics
1 answer:
-Dominant- [34]3 years ago
4 0
The answer is C.
7+9 = 16
16×150 = 2400
4500-2400 = 2100
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Please help for 10 ponits
Vedmedyk [2.9K]

Answer:

it's a yes

Step-by-step explanation:

X/6 ≤ 30

to find the value of X we have to move the numerical to the other side

in this case the number is 1/6

X * 1/6 ≤ 30

so to balance the both side and get rid of the number on the left side we multiple with 6.

1/6*6 = 1 on the left side

30*6 = 180 on the right side

so the full equation will be

X * 1/6 * 6 ≤ 30 * 6

X * 1 ≤ 180

X ≤ 180

6 0
3 years ago
Read 2 more answers
What changes when the parent function <img src="https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2" id="TexFormula1" title="f(x)=x^2" alt=
Karolina [17]

9514 1404 393

Answer:

  • vertical stretch: the function value (f) is multiplied by the stretch factor
  • horizontal stretch: the variable (x) is divided by the stretch factor

Step-by-step explanation:

A stretch can be vertical, horizontal, or both.

Multiplying the function value by a factor greater than 1 will stretch the graph vertically.

Dividing the variable value by a factor greater than 1 will stretch the graph horizontally.

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The graph is stretched by the factor according to how it is applied.

6 0
3 years ago
Quadrilateral ABCD has vertices at A(0,0), B(0,2), C(6,2), and D(6,0). Find the vertices of the quadrilateral after a dilation w
valentinak56 [21]

Answer:

A=0

B=0,3

C=9,3

D=9,0

Step-by-step explanation:

Multiplies all the vertices bay scale factor 3/2

5 0
3 years ago
The value 5 is an upper bound for the zeros of the function shown below.
Mice21 [21]

Answer:

The given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18  will be true.

Step-by-step explanation:

Given

f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18

We know the rational zeros theorem such as:

if x=c is a zero of the function f(x),

then f(c) = 0.

As the f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18 is a polynomial of degree 4, hence it can not have more than 4 real zeros.

Let us put certain values in the function,

f(5) = 448, f(4) = 126, f(3) = 0, f(2) = -20,

f(1) = 0, f(0) = 18, f(-1) = 16, f(-2) = 0, f(-3) = 0

From the above calculation results, we determined that 4 zeros as

x = -3, -2, 1, and 3.

Hence, we can check that

f(x) = (x+3)(x+2)(x-1)(x-3)

Observe that,

for x > 3, f(x) increases rapidly, so there will be no zeros for x>3.

Therefore, the given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18  will be true.

5 0
3 years ago
I’ll give brainliest
kupik [55]

Answer:

Area= (12^2)pi

Step-by-step explanation:

Area= 150/360 (pi12^2)

= 188.5 total area

5 0
3 years ago
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