Question

A pet Shop manager wants the dame number of birds in each cage. He wants to use as few cages possible, but can only have one type of bird in each cage. If he has 42 parakeets and 18 canaries, how many birds will he put in each cage?

Answer 1

42 divided by 7 =6

18 divided by3 =6

7+3=10 cages

Answer 2

Answer:

The manager will put 6 parakeets each in 7 cages and 6 canaries each in 3 cages.

Step-by-step explanation:

We will find the greatest common factor of 42 and 18 to know the answer.

42 = 2 x 3 x 7

18 = 2 x 3 x 3

So, greatest common factor is $2\times3=6$

So, 42 parakeets need $42/6 =7$ cages

And 18 canaries need $18/6=3$ cages

So, the manager will put 6 parakeets each in 7 cages and 6 canaries each in 3 cages.