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2 years ago

Ica ingin membuat sebuah lampion

Mathematics

1 answer:

podryga [215]2 years ago

7 0

Well the answer is 3,375

You might be interested in

-3x+4y=-10 in y=mx+b

belka [17]

Y = 3/4x -5/2

Hope this helps!

8 0

3 years ago

The net of a square pyramid is shown

Wewaii [24]

Answer:

Option (D)

Step-by-step explanation:

Surface area of a square pyramid is determined from the formula,

Surface area = Area of the square base + 4(Area of one lateral triangular side)

Area of the base = (Side)²

= 8²

= 64 cm²

Area of one lateral triangle = $\frac{1}{2}(\text{Base})(\text{Height})$

= $\frac{1}{2}(8)(8)$

= 32 cm²

Therefore, surface area of the square pyramid = 64 + 4(32)

= 64 + 128

= 192 cm²

Therefore, Option (D) will be the correct option.

3 0

2 years ago

Someone please help myst teacher never explains the hw

harina [27]

Answer:

Prob gonna be prob b

Step-by-step explanation:

3 0

3 years ago

Carly said that 0.8÷10=0.04. Is she correct? Explain how you know.

faust18 [17]

Answer:

To divide 0.8 divided by 20 she needs to annex a 0 in the hundredths place. So, the quotient is 0.04, and Carly is correct

3 0

3 years ago

The sum of the diagonals of a rhombus is 5√2.

Alex

Greetings!
Let ABCD be a rhombus
AC + BD = 5√2 cm

Area of ABCD = Ar△ABD + Ar △BCD
$= \frac{1}{2} \times BD \times AO + \frac{1}{2} \times BD \times OC$
$= \frac{1}{2} BD (AO + OC)$
$\frac{1}{2} BD \times AC$

$So, \frac{ BD \times AC}{2} = 4 \: cm {}^{2}$
$BD \times AC = 8$
$Now, AC + \: BD = 5 \sqrt{2}$

Squaring both sides, we get
$AC {}^{2} + BD {}^{2} + 2 AC.BD =50$
$AC {}^{2} + BD {}^{2} + 2 \times 8 = 50$
$AC {}^{2} + BD {}^{2} = 50 - 16$
$AC {}^{2} + BD {}^{2} = 34$

In △AOB, we have
$OA {}^{2} + OB {}^{2} =AB {}^{2}$
$( \frac{ AC }{2} ) {}^{2} + ( \frac{ BD}{2} ) {}^{2} = AB {}^{2}$
$\frac{ AC {}^{2} } {4} + \frac{ BD {}^{2} }{4} = AB {}^{2}$
$AC {}^{2} + BD {}^{2} = 4 AB {}^{2}$
$34 = 4 AB {}^{2}$

Square rooting both sides
$\sqrt{34} = 2 AB$
$Perimeter = 4 \: AB \\ = 2 \times 2 \: AB \\ = 2 \: \times \sqrt{34 } \\ = 2 \sqrt{34 \: } units$ .

Hope it helps!

7 0

3 years ago