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2 years ago

8

LeAnn wants to giftwrap a present she got for her little brother. How many square inches of giftwrap will be needed to cover a b

ox that is 5in x 7in x 3in?

1 answer:

Crazy boy [7]2 years ago

7 0

Just find the surface area. 5*7=35, but 35*2=7<span>0</span>, because the top and bottom. Then do 7*3*2=42, for 2 parallel sides, and then 3*5*2=30. Now add 70+30+42=142 square inches. There's your answer.

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Which algebraic property could be used to rewrite 4x + 2y as 2y + 4x? (3 points)

MAXImum [283]

Answer:

C = commutative property of Addition

5 0

2 years ago

Read 2 more answers

Y=4x+8x, Solve for x.<br><br> It's x=y/12, I just need to know how to work it out.

Scrat [10]

Step-by-step explanation:

<h2>Answer:-</h2>

$\tt{y = 4x+8x}$

First, we need to add up the x.

We know that 4+8 = 12, so

$\tt{4x+8x=12x}$

Now, equating it to y,

$\tt{y = 12x}$

Now, if I multiply $\tt{\dfrac{1}{12}}$ on both sides,

I get,

$\tt{\dfrac{y}{12}= \dfrac{\cancel{12}x}{\cancel{12}}}$

Now, as 12 got cancelled , I got the final answer as

$\boxed{\tt{x =\dfrac{y}{12}}}$

Hope it helps :)

4 0

2 years ago

59 and/or 60. Determine if the triangles are similar. If they are similar, find the scale factor from ABC to JKL.

navik [9.2K]

9514 1404 393

Answer:

59) not similar

60)

Step-by-step explanation:

59) The ratios of the side lengths shown cannot be reduced. They are different, so the triangles are not similar.

7:8:12 ≠ 6:7:11

__

60) The side length ratios both reduce to 8:7:10, so the triangles are similar.

∆ABC ~ ∆JKL

The scale factor is LJ/CA = 25/20 = 5/4. (Multiplying ABC by 5/4 will give JKL.)

8 0

2 years ago

What is the value or x?

Romashka [77]

From the given figure

$\cos x=\frac{XY}{XZ}$

Since XY = 5.1 and XZ = 7.7, then

$\cos x=\frac{5.1}{7.7}$

To find x, use the inverse of cos

$x=\cos ^{-1}(\frac{5.1}{7.7})$

Use the calculator to find x

$x=48.522$

The answer is

4 0

9 months ago

The one-to-one functions g and h are defined as follows

Debora [2.8K]

Answer:

$g^-^1(x)=-8$

$h^-^1(x)=\frac{x-4}{3}$

$(h^-^1 \ o\ h)(-3)=-3$

Step-by-step explanation:

When given the following functions,

$g=[(-2,-7),(4,6),(6,-8),(7,4)]$

$h(x)=3x+4$

One is asked to find the following,

1. Question 1

$g^-^1(4)$

When finding the inverse of a function that is composed of defined points, one substitutes the input given into the function, then finds the output. After doing so, one must substitute the output into the function, and find its output. Thus, finding the inverse of the given input;

$g^-^1(4)$

$g(4)=6\\g(6)=-8\\g^-^1(4)=-8$

2. Question 2

$h^-^1(x)$

Finding the inverse of a continuous function is essentially finding the opposite of the function. An easy trick to do so is to treat the evaluator (h(x)) like another variable. Solve the equation for (x) in terms of (h(x)). Then rewrite the equation in inverse function notation,

$h(x)=3x+4\\\\h(x)-4=3x\\\\\frac{h(x)-4}{3}=x\\\\\frac{x-4}{3}=h^-^1(x)$

$h^-^1(x)=\frac{x-4}{3}$

3. Question 3

$(h^-^1 \ o\ h)(-3)$

This question essentially asks one to find the composition of the function. In essence, substitute function (h) into function ( $h^-^1$ ) and simplify. Then substitute (-3) into the result.

$h^-^1\ o\ h$

$\frac{(3x+4)-4}{3}\\\\=\frac{3x+4-4}{3}\\\\=\frac{3x}{3}\\\\=x$

Now substitute (-3) in place of (x),

$=-3$

8 0

2 years ago