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Artemon [7]
3 years ago
11

One pump can empty a pool in 4 days, whereas a second pump can empty the pool in 10 days. How long will it take the two pumps, w

orking together, to empty the pool? (Fractional answers are OK.)
Mathematics
1 answer:
gtnhenbr [62]3 years ago
7 0

Answer:

20/7 days (just less than 3 days)

Step-by-step explanation:

Recall that (1 job) = (rate)(time), so time = (1 job) / (rate).

Set up and solve the following equation:

  1 job

------------------------------- = time required for 2 pumps working together

1 job         1 job

---------- + -------------

4 days      10 days

This comes out to:

              1 job

------------------------------------------- = time required

10 job-days      4 job-days

------------------ + -----------------

   40 days           40 days

or:

    1 job

-------------------- = (40/14) days, or 20/7 days (just less than 3 days)

14 job·days

-----------------

   40 days  

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Please create a word problem using the concept of probability. Please provide the answer to your word problem. *
vitfil [10]

In a game of rock paper scissors, what are the chances that someone playing against a person playing only paper would win?

As for the answer, if you were to make a chart to show rock, paper, and scissors, you'd be able to see that there's a 2/3 chance of winning by choosing rock. With scissors, there's also a 2/3 chance to win. Now with paper, there's only a 1/3 chance to win. Knowing that the other person will only play paper, the best answers would be to choose either rock or scissors.

(there are, of course, flaws with this concept, because the opponent could be lying about playing only paper. More or less, it's a good design to show probability.)

7 0
3 years ago
Please help! Two math problems!!!
Fynjy0 [20]

Answer:

Tell me if i am wrong. :)

Step-by-step explanation:

To solve for y:

Q.1   2x + y = -1

       y = -1 - 2x

Q. 2.  4x - 5y = 7

        y = 7 - 4x over -5

 

3 0
3 years ago
Mrs Adams baked some muffins. Carl eat 2/5 of the muffins and John eat 25. How many muffins were baked?
Dennis_Churaev [7]

Answer:


Well, how many were left over? Mrs. Adams has a muffin factory and made 1 million muffins. Carl ate 2/5 or 40% or 400,000 muffins, and John ate 25. 599,975 muffins were shipped for sale. That meets the stated requirements.


Hence, we have to guess there were supposed to be no muffins left over.


In that case, Mrs. Adams baked 125/3 muffins, Carl ate 2/5 of them = 50/3, leaving 75/3 = 25 for John.



Step-by-step explanation:

x muffins baked, 2/5 eaten by Carl, 3/5 left to be eaten by John, who ate 25 before running out.


3/5 x = 25

x = 25 × 5/3 = 125/3 = 41 + 2/3


Or, Start with x muffins. Carl ate 2/5 x, leaving 3/5 x. John ate 25 with zero left over. So 3/5 x = 25.


(x - 2/5 x) - 25 = 0

3/5 x = 25

x = (5/3) × 25 = 125/3.

8 0
3 years ago
How to classify 17/10
storchak [24]

Answer:

rational

Step-by-step explanation:

4 0
3 years ago
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A radar gun was used to record the speed of a swimmer (in meters per second) during selected times in the first 2 seconds of a r
Natalka [10]
Trapezoidal is involving averageing the heights
the 4 intervals are
[0,4] and [4,7.2] and [7.2,8.6] and [8.6,9]

the area of each trapezoid is (v(t1)+v(t2))/2 times width

for the first interval
the average between 0 and 0.4 is 0.2
the width is 4
4(0.2)=0.8

2nd
average between 0.4 and 1 is 0.7
width is 3.2
3.2 times 0.7=2.24

3rd
average betwen 1.0 and 1.5 is 1.25
width is 1.4
1.4 times 1.25=1.75

4th
average betwen 1.5 and 2 is 1.75
width is 0.4
0.4 times 1.74=0.7

add them all up
0.8+2.24+1.75+0.7=5.49

5.49
t=time
v(t)=speed
so the area under the curve is distance
covered 5.49 meters
8 0
3 years ago
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