In a game of rock paper scissors, what are the chances that someone playing against a person playing only paper would win?
As for the answer, if you were to make a chart to show rock, paper, and scissors, you'd be able to see that there's a 2/3 chance of winning by choosing rock. With scissors, there's also a 2/3 chance to win. Now with paper, there's only a 1/3 chance to win. Knowing that the other person will only play paper, the best answers would be to choose either rock or scissors.
(there are, of course, flaws with this concept, because the opponent could be lying about playing only paper. More or less, it's a good design to show probability.)
Answer:
Tell me if i am wrong. :)
Step-by-step explanation:
To solve for y:
Q.1 2x + y = -1
y = -1 - 2x
Q. 2. 4x - 5y = 7
y = 7 - 4x over -5
Answer:
Well, how many were left over? Mrs. Adams has a muffin factory and made 1 million muffins. Carl ate 2/5 or 40% or 400,000 muffins, and John ate 25. 599,975 muffins were shipped for sale. That meets the stated requirements.
Hence, we have to guess there were supposed to be no muffins left over.
In that case, Mrs. Adams baked 125/3 muffins, Carl ate 2/5 of them = 50/3, leaving 75/3 = 25 for John.
Step-by-step explanation:
x muffins baked, 2/5 eaten by Carl, 3/5 left to be eaten by John, who ate 25 before running out.
3/5 x = 25
x = 25 × 5/3 = 125/3 = 41 + 2/3
Or, Start with x muffins. Carl ate 2/5 x, leaving 3/5 x. John ate 25 with zero left over. So 3/5 x = 25.
(x - 2/5 x) - 25 = 0
3/5 x = 25
x = (5/3) × 25 = 125/3.
Answer:
rational
Step-by-step explanation:
Trapezoidal is involving averageing the heights
the 4 intervals are
[0,4] and [4,7.2] and [7.2,8.6] and [8.6,9]
the area of each trapezoid is (v(t1)+v(t2))/2 times width
for the first interval
the average between 0 and 0.4 is 0.2
the width is 4
4(0.2)=0.8
2nd
average between 0.4 and 1 is 0.7
width is 3.2
3.2 times 0.7=2.24
3rd
average betwen 1.0 and 1.5 is 1.25
width is 1.4
1.4 times 1.25=1.75
4th
average betwen 1.5 and 2 is 1.75
width is 0.4
0.4 times 1.74=0.7
add them all up
0.8+2.24+1.75+0.7=5.49
5.49
t=time
v(t)=speed
so the area under the curve is distance
covered 5.49 meters
