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Zielflug [23.3K]
3 years ago
13

What is the slope of the line that passes through the points (6, 7) and (4, 1)?

Mathematics
1 answer:
dezoksy [38]3 years ago
4 0

Answer:

The answer is 3 Hope this help :)

Step-by-step explanation:(6,7) (4,1)

\frac{y2-y1}{x2-x1}

\frac{1-7}{4-6}

\frac{-6}{-2}

x=3

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-4x - y = 24<br> Complete the missing value in the solution to the equation.<br> ( _,8)
Zinaida [17]

Answer:

(- 8, 8 )

Step-by-step explanation:

Given ( ?, 8 ) is a solution. To find x substitute y = 8 into the equation, then

- 4x - 8 = 24 ( add 8 to both sides )

- 4x = 32 ( divide both sides by - 4 )

x = - 8

Thus solution is (- 8, 8 )

5 0
2 years ago
Which represents the numbers in order from least to greatest?<br> 9%, 9/10, 9. -9/1
DaniilM [7]

Answer:

9% 9. -9/1 9/1

Step-by-step explanation:

8 0
3 years ago
What is the least common multiple? (6 and 12)​
quester [9]

Answer:Least common multiple ( LCM ) of 6 and 12 is 12. LCM(6,12) = 12. Least common multiple or lowest common denominator (lcd) can be calculated in two way; with the LCM formula calculation of greatest common factor (GCF), or multiplying the prime factors with the highest exponent factor.

Step-by-step explanation:

6 0
2 years ago
Tickets to a school play cost $3 for students and $8 for adults. on opening night, $1840 was collected and 360 tickets sold. use
Pachacha [2.7K]

Answer:

240a (adults) 120s ( students ) hope that helped

Step-by-step explanation:

3/360 8/1840

5 0
3 years ago
What is the horizontal asymptote of the rational function f(x) = 3x / (2x - 1)?
-BARSIC- [3]

Answer:

Step-by-step explain

Find the horizontal asymptote for f(x)=(3x^2-1)/(2x-1) :

A rational function will have a horizontal asymptote of y=0 if the degree of the numerator is less than the degree of the denominator. It will have a horizontal asymptote of y=a_n/b_n if the degree of the numerator is the same as the degree of the denominator (where a_n,b_n are the leading coefficients of the numerator and denominator respectively when both are in standard form.)

If a rational function has a numerator of greater degree than the denominator, there will be no horizontal asymptote. However, if the degrees are 1 apart, there will be an oblique (slant) asymptote.

For the given function, there is no horizontal asymptote.

We can find the slant asymptote by using long division:

(3x^2-1)/(2x-1)=(2x-1)(3/2x+3/4-(1/4)/(2x-1))

The slant asymptote is y=3/2x+3/4

6 0
3 years ago
Read 2 more answers
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