Answer:
Reject H0; there is significant evidence that the proportion of site users who get their world news on this site has changed since 2013 and is significantly different from 45%
Step-by-step explanation:
Sample size, n = 3603
x = 1697
Phat = x/n = 1697/3603 = 0.4709 =47.09%
H0 : p = 0.45
H1 : p > 0.45
The test statistic :
(phat - p) / sqrt[(p(1 - p)) /n]
(0.4709 - 0.45) / sqrt[(0.45(0.55))/3603]
0.0209 / 0.00828810932
Test statistic = 2.5217
The Pvalue :
Using the Pvalue from Test statistic calculator ; α = 0.05 ;
Pvalue at 95% confidence = 0.005839
Pvalue < α ;
Hence, we reject the Null
Therefore, we conclude that the sample gives evidence that the proportion of site users who get their world news on this site has changed since 2013.
Your answer is b because 95% of data is ideally with 2 deviations from the mean and 99.9% of data is within 3 deviations from the mean.
Answer:
I don't know what it is bc i'm on a school laptop and it won't let me see it
Step-by-step explanation:
Answer:
-4a +22b
Step-by-step explanation:
add the ones with same variable
Answer:
P(B|S) = 0.95
Step-by-step explanation:
Hello!
A certain company claims that its e-mail filter has 95% accuracy.
Be the events
S: The e-mail is Spam.
B: The filter blocks a message.
If the filter has 95% accuracy it means that it'll block 95% of the spam, another way to put it is that out of 100 spam messages the filter will block 95 of them.
Expressing it in terms of probability we can say that the probability of the filter blocking a message given that it is spam is 0.95, symbolically P(B/S)=0.95
I hope you have a SUPER day!