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The first term of the arithmetic progression exists at 10 and the common difference is 2.
<h3>How to estimate the common difference of an arithmetic progression?</h3>
let the nth term be named x, and the value of the term y, then there exists a function y = ax + b this formula exists also utilized for straight lines.
We just require a and b. we already got two data points. we can just plug the known x/y pairs into the formula
The 9th and the 12th term of an arithmetic progression exist at 50 and 65 respectively.
9th term = 50
a + 8d = 50 ...............(1)
12th term = 65
a + 11d = 65 ...............(2)
subtract them, (2) - (1), we get
3d = 15
d = 5
If a + 8d = 50 then substitute the value of d = 5, we get
a + 8 5 = 50
a + 40 = 50
a = 50 - 40
a = 10.
Therefore, the first term is 10 and the common difference is 2.
To learn more about common differences refer to:
#SPJ4
Answer:
Step-by-step explanation:
We have to calculate the time derivative of T=PV/nR with P and V variable and n and R constants. This is:
What we have to do is the derivative of a product:
Substituting, we have:
where all these values are given since the time derivatives of P and V are their variation rate, using minutes.
We then substitute everything, noticing that already everything is in the same system of units so they cancel out:
And then just calculate: