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3 years ago

The ratio of the profit, material cost and production labour of an article is 5:7:13.

Mathematics

1 answer:

IRINA_888 [86]3 years ago

8 0

Answer:

The cost of producing the article is -3500 (Negative cost)

Step-by-step explanation:

The given parameters are

The ratio of the profit to material cost to production labor = 5:7:13

The amount of the material cost = 840 + Labor cost

Let the total cost = X

Therefore, we have;

The fraction of the total cost that is material cost = 7/(5 + 7 + 13) = 7/25

Therefore, the material cost = 7/25 × X

The fraction of the total cost that is labor cost = 13/(5 + 7 + 13) = 13/25

Therefore, the labor cost = 13/25 × X

However, the amount of the material cost = 840 + Labor cost, which gives;

7/25 × X = 13/25 × X + 840

7/25 × X - 13/25 × X = 840

-6/25 × X= 840

X = 840/(-6/25) = 840×(-25/6) = -3500

The cost of producing the article = -3500.

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THE GRAPH IS BELOW THANKS :) Anika is on the crew to set up rides for the state fair. The crew does most of the setup on the day

Vaselesa [24]

Answer:

(a) We will form an equation of line from the points given (6,10) and (2,15)

Using: $y-y_1=\frac{y_2-y_1}{x_2-x_1}\cdot (x-x_1)$

On substituting the values in the formula above we will get the required equation of line.

$y-10=\frac{15-10}{2-6}\cdot (x-6)$

$\Rightarrow y-10=\frac{5}{-4}\cdot (x-6)$

On simplification we will get:

$y=\frac{1}{4}(-5x+70)$

(b) We need to tell at day 0 put x=0 in above equation:

$y=\frac{1}{4}(-5\cdot 0+70)$

$y=70$

Anika worked for 70 hours on the set up crew on the day the fair arrived at the fairgrounds day 0.

Now, we need to tell decrease per day which is equal to the slope of line

To find the slope compare the equation with general equation which is y=mx+c where m is slope

Here, in $y=\frac{1}{4}(-5x+70)$

$m=\frac{-5}{4}$ which is the decrease per day.

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3 years ago

Which function is the same as y = 3 cosine (2 (x startfraction pi over 2 endfraction)) minus 2? y = 3 sine (2 (x startfraction p

kirza4 [7]

The function which is same as the function y = 3cos(2(x +π/2)) -2 is: Option A: y= 3sin(2(x + π/4)) - 2

<h3>How to convert sine of an angle to some angle of cosine?</h3>

We can use the fact that:

$\sin(\theta) = \cos(\pi/2 - \theta)\\\sin(\theta + \pi/2) = -\cos(\theta)\\\cos(\theta + \pi/2) = \sin(\theta)$

to convert the sine to cosine.

<h3>Which trigonometric functions are positive in which quadrant?</h3>

In first quadrant (0 < θ < π/2), all six trigonometric functions are positive.
In second quadrant(π/2 < θ < π), only sin and cosec are positive.
In the third quadrant (π < θ < 3π/2), only tangent and cotangent are positive.
In fourth (3π/2 < θ < 2π = 0), only cos and sec are positive.

(this all positive negative refers to the fact that if you use given angle as input to these functions, then what sign will these functions will evaluate based on in which quadrant does the given angle lies.)

Here, the given function is:

$y= 3\cos(2(x + \pi/2)) - 2$

The options are:

$y= 3\sin(2(x + \pi/4)) - 2$
$y= -3\sin(2(x + \pi/4)) - 2$
$y= 3\cos(2(x + \pi/4)) - 2$
$y= -3\cos(2(x + \pi/2)) - 2$

Checking all the options one by one:

Option 1: $y= 3\sin(2(x + \pi/4)) - 2$

$y= 3\sin(2(x + \pi/4)) - 2\\y= 3\sin (2x + \pi/2) -2\\y = -3\cos(2x) -2\\y = 3\cos(2x + \pi) -2\\y = 3\cos(2(x+ \pi/2)) -2$

(the last second step was the use of the fact that cos flips its sign after pi radian increment in its input)
Thus, this option is same as the given function.

Option 2: $y= -3\sin(2(x + \pi/4)) - 2$

This option if would be true, then from option 1 and this option, we'd get:
$-3\sin(2(x + \pi/4)) - 2= -3\sin(2(x + \pi/4)) - 2\\2(3\sin(2(x + \pi/4))) = 0\\\sin(2(x + \pi/4) = 0$