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3 years ago

Write the equation that passes through the following points: (5,0) and (−10,−5)

Mathematics

1 answer:

Vikentia [17]3 years ago

4 0

Answer:

The answer is:

$y = \frac{1}{3} x - \frac{5}{3}$

Step-by-step explanation:

❃Incase you forgot what the linear equation formula is ☟

$y = mx + b$

❃Incase you also forgot, The is what the slope formula is ☟

$m = \frac{y_2 - y_1 }{x_2 - x_1}$

➊ First: We are going to be solving for the slope.

$m = \frac{ - 5 - 0}{ - 10 - 5} = \frac{ - 5}{ - 15} = \frac{1}{3}$

➋Second: We find the y-intercept.

$y = mx + b \\ 0 = \frac{1}{3} (5) + b \\ 0 = \frac{5}{3} + b \\ \frac{ - \frac{5}{3} = - \frac{5}{3 } \: \: \: \: \: \: \: \: \: \: \: \: }{ - \frac{5}{3} = b}$

➌Third: Plug in.

$y = \frac{1}{3} x - \frac{5}{3}$

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Can somone please help with delta math??

Aleksandr-060686 [28]

Answer:

yea sure

Step-by-step explanation:

5 0

3 years ago

Solve the system of linear equations for x and y.(cos θ)x + (sin θ)y=1(−sin θ)x + (cos θ)y = 0x=y=

lys-0071 [83]

Answer:

$\bold{x =cos\theta}\\\bold{y=sin\theta}$

Step-by-step explanation:

The given system of linear equations is:

$(cos\theta)x+(sin\theta)y=1\\(-sin\theta)x+(cos\theta)y=0$

We have to solve the equations for the values of $x, y$ .

Let us use elimination method in which we eliminate one of the variables from the two variables.

For this, let us multiply the first equation by $sin\theta$ and second equation by $cos\theta$

Now, the equations become:

$(cos\theta.sin\theta)x+(sin\theta.sin\theta)y=sin\theta\\\Rightarrow (cos\theta.sin\theta)x+(sin^2\theta)y=sin\theta ....... (1)\\\\(-sin\theta.cos\theta)x+(cos\theta.cos\theta)y=0\\\Rightarrow (-sin\theta.cos\theta)x+(cos^2\theta)y=0 ..... (2)$

Now, let us add (1) and (2):

$(sin^2\theta)y+(cos^2\theta)y=sin\theta\\\Rightarrow (sin^2\theta+cos^2\theta)y=sin\theta\\\Rightarrow (1)y=sin\theta\\\Rightarrow y = sin\theta$

Using the equation:

$(-sin\theta)x+(cos\theta)y=0$

Putting value of $y$ :

$\Rightarrow (-sin\theta)x+(cos\theta)sin\theta=0\\\Rightarrow (sin\theta)x=(cos\theta)sin\theta\\\Rightarrow x = cos\theta$

So, the answer to the system of linear equations is:

$\bold{x =cos\theta}\\\bold{y=sin\theta}$

7 0

3 years ago

After a dilation with center (0,0) the image of DB is D’B’ if DB=6 and D’B’=2 the scale factor of dilation is what ?

bezimeni [28]

Answer:

scale factor = $\frac{1}{3}$

Step-by-step explanation:

the scale factor is the ratio of corrresponding sides. image to original.

scale factor = $\frac{D'B'}{DB}$ = $\frac{2}{6}$ = $\frac{1}{3}$

7 0

2 years ago

nobodys probably gonna answer this ): but if you can please do with the answers its for my homework :)

kotegsom [21]

<u>Answer</u>

<h3>12 ) $1000</h3><h3 /><h3>13 ) Y-Intercept = 1000</h3><h3> Slope = $\frac{3000-2000}{4-2}$ = $\frac{1000}{2}$ = $\frac{500}{1}$ </h3><h3 /><h3>14 ) $\left(x^{1\ },\ y^{1}\right)\left(x^{2},\ y^{2}\right)$ → $\left(2\ ,\ 2000\right)\ \left(4\ ,\ 3000\right)$ → $\frac{3000-2000}{4-2}$ → $\frac{500}{1}$ </h3><h3 /><h3>15 ) The meaning of the slope is the steepness of the line, in this graph, the meaning is 500 over 1.</h3><h3 />

<em>Hope this helps! <3</em>

<h2 />

6 0

3 years ago

Find the value of x and the value of y

serg [7]

Answer:

Step-by-step explanation:

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

use Cos for y .... b/c we see that function above has all the pieces we are going to work with

use Sin for x .. for the same reason above

Cos(30) = y / 4 $\sqrt{2}$

4 $\sqrt{2}$ Cos(30) = y

4 $\sqrt{2}$ $\sqrt{3}$ /2 = y

2 $\sqrt{6}$ = y

leave the answer for y like that.. it's in 'exact" form

now for x

Sin(30) = x / 4 $\sqrt{2}$

4 $\sqrt{2}$ Sin(30) = x

4 $\sqrt{2}$ * 1/2 = x

2 $\sqrt{2}$ = x

and leave your answer for x like that as it's in it's exact form. :)

oh and I see the answer in the list.. do you? :)

8 0

3 years ago