Question

Appreciate answers and any help!

Answer 1

To find the expected value of the distribution, we multiply each outcome by it's probability. Doing this, we get that the expected value of defects on a skateboard is of $\frac{4}{25}$.

Outcomes and probabilities:

0 defects, 9/10 probability

1 defect, 1/20 probability

2 defects, 1/25 probability

3 defects, 1/100 probability.

Expected value:

$E(X) = 0\frac{9}{10} + \frac{1}{20} + 2\frac{1}{25} + 3\frac{1}{100} = \frac{1}{20} + \frac{2}{25} + \frac{3}{100} = \frac{5 + 8 + 3}{100} = \frac{16}{100}$

Dividing both numerator and denominator by 4:

$\frac{4}{25}$

Thus, the expected value of defects on a skateboard is of $\frac{4}{25}$.

A similar problem is given at: brainly.com/question/23156292.