Answer:
see explanation
Step-by-step explanation:
(a)
Given
2k - 6k² + 4k³ ← factor out 2k from each term
= 2k(1 - 3k + 2k²)
To factor the quadratic
Consider the factors of the product of the constant term ( 1) and the coefficient of the k² term (+ 2) which sum to give the coefficient of the k- term (- 3)
The factors are - 1 and - 2
Use these factors to split the k- term
1 - k - 2k + 2k² ( factor the first/second and third/fourth terms )
1(1 - k) - 2k(1 - k) ← factor out (1 - k) from each term
= (1 - k)(1 - 2k)
1 - 3k + 2k² = (1 - k)(1 - 2k) and
2k - 6k² + 4k³ = 2k(1 - k)(1 - 2k)
(b)
Given
2ax - 4ay + 3bx - 6by ( factor the first/second and third/fourth terms )
= 2a(x - 2y) + 3b(x - 2y) ← factor out (x - 2y) from each term
= (x - 2y)(2a + 3b)
Answer:
A
Step-by-step explanation:
Edge 2021
We can solve this by finding one of the numbers first
Let the smaller number be y.
Since these 2 numbers are consecutive odd numbers, the larger number should be 2 more than the smaller one (y+2).
Therefore,
y + (y+2) = 284
2y +2 = 284
shift +2 to the other side and turn it into -2
2y = 284 - 2
2y = 282
shift x2 to the other side and turn it into /2
y = 282/2
y = 141
Now we got the smaller number, which is 141, we can also find the larger number by adding 2 to it. 141+2 = 143,
Therefore, your answer is 141 and 143
Answer:
yes i think u are correct
Step-by-step explanation:
Answer:
c
Step-by-step explanation:
