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exis [7]
3 years ago
7

Use the vertical line test to determine whether or not the graph is a graph of a function.

Mathematics
1 answer:
netineya [11]3 years ago
6 0

Answer:

29 is yes

and

30 is no

Step-by-step explanation:

hope this helpss

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If the midpoint of (4, 3) and point A has coordinates (-2, 6), what are the coordinates of point B?
baherus [9]
(xA+xB)/2, (yA+yB)/2 = (4,3)
(xA+xB)/2 = 4
(-2+xB) = 8 --> xB = 8+2 --> xB = 10
(yA+yB)/2 = 3
(6+yB) = 6 --> yB = 6-6 --> yB = 0

B = (10,0)
5 0
3 years ago
One of the legs of a right triangle is 9 cm. If the area of the triangle is 225 cm², then the length of the other leg is
ioda

Given:

One of the legs of a right triangle is 9 cm.

The area of the triangle is 225 cm².

To find:

The length of the other leg.

Solution:

The area of a triangle is

Area=\dfrac{1}{2}\times Base\times Height

The area of a right triangle is

Area=\dfrac{1}{2}\times (leg_1)\times (leg_2)

Let x be the length of other leg.

225=\dfrac{1}{2}\times (9)\times (x)

2\times 225=9x

\dfrac{450}{9}=x

50=x

Therefore, the length of the other leg is 50 cm.

4 0
3 years ago
What is the formula for the area of a rectangle?
PtichkaEL [24]

Answer:

The area of a rectangle is length*width

Step-by-step explanation:

The answer is A

This is simple

6 0
3 years ago
Read 2 more answers
You randomly choose one of the morales.Without replacing the first marble, you choose a second marble. What is the probability o
IrinaK [193]
Let’s say, hypothetically speaking, you chose the second marble without replacing the first marble so, events are hypothetically dependent. Events are dependent if the occurrence of one hypothetical event hypothetically does affect the likelihood that the other events occur. The probably of two or more dependent events A and B is the probability of A times the probability of B after A hypothetically occurs

P(A and B) = P(A) x P(B after A)

Choose the first marble

The total number of hypothetical marbles are, hypothetically speaking, 4 on a hypothetical basis, and there is one red marble.

P(red)=1/4

Choose the second marble

Without hypothetically replacing the hypothetical first marble, you choose the hypothetical marble, hypothetically speaking. So, the total hypothetical number of marbles are, hypothetically, 3, and there is, hypothetically, one green marble.

P(green) = 1/3

The probability of choosing red and then, hypothetically, green is:

P(red and green) = P(red) x P(green)
=1/4 x 1/3

= 1/12

P(red and green) is hypothetically equal to 1/12 on a hypothetical account.

Final hypothetical answer: 1/12
4 0
2 years ago
Anyone have any idea of what this could be please help asap
fiasKO [112]

Answer:

20

Step-by-step explanation:

divided 12 by three since it mirrors the shape on a smaller scale. you get 4. multiply that by five and there's your answer

8 0
2 years ago
Read 2 more answers
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