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Sveta_85 [38]
3 years ago
5

Which number is a counting number? Can you do both of them plz

Mathematics
1 answer:
DochEvi [55]3 years ago
4 0
Question 3 is: D. All integers are rational numbers.
Question 4 is: C. the counting number is 4. Hope this helped :)
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A schools principal wants to determine which type of speaker the students prefer to invite to an assembly for the entire student
frosja888 [35]
For a survey like this, you want to take a random sample. It would be a good idea to use an alphabetical list of the students. Then, you could randomly select students from the list.

The principal would want to avoid surveying all the same type of students. For example, don't just ask the athletes.
7 0
3 years ago
What is the factorization of the polynomial below?<br> 5x2 - 35x + 60
natita [175]

Answer:

5(x-3)(x-4)

Step-by-step explanation:

5x^2-35x+60

Start by factoring out a 5:

5(x^2-7x+12)

We need to find two integers that have a product of 12, and a sum of -7:

(-3)(-4)=12

-3-4=-7

We can split -7x into -3x and -4x

5(x^2-3x-4x+12)

Factor each half separately:

5[x(x-3)-4(x-3)]

Since x and -4 are both being multiplied by x-3, we can combine them:

5(x-3)(x-4)

7 0
2 years ago
PLS HELP WILL GIVE BRANLIEST
BartSMP [9]
The answer is A if I am correct
3 0
2 years ago
Jacob has several babysitting jobs.on one job ,he earned $10 an hour plus an extra $20 since there were 3 children.On another jo
Umnica [9.8K]

Answer:

4 hours, $60

Step-by-step explanation:

6 0
2 years ago
Which expression is equivalent to sqrt2/^3sqrt2
zimovet [89]

The given expression is \frac{\sqrt{2}}{\sqrt[3]{2}}

This can be simplified using the radical properties as below

\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}} \\\\   \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}} \\\\

Now using exponent properties we can write

\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}}=2^{\frac{1}{2}-\frac{1}{3}} \\\\\frac{\sqrt{2}}{\sqrt[3]{2}}=2^{\frac{3-2}{6}}=2^\frac{1}{6}\\\\= \sqrt[6]{2}\\

7 0
3 years ago
Read 2 more answers
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