Answer:
3p² + 32p + 13
Step-by-step explanation:
Okay, so lets first solve for 2b. 2b = 2(p + 5), which is equal to 2p + 10. Now, let's solve for 3a. 3a = 3(p² + 10p +1), simplifying to 3p² + 30p +3. After adding 2b and 3a, we are able to get 2p + 10 + 3p² + 30p + 3 = 3p² + 32p + 13
+ 19 on both sides, -19 becomes 0, 1 becomes 20 x=20
In one day, there are 24 hours. In 1 hour, there are 3,600 seconds. So, that means that there are 86,400 seconds. Also, in 1 day, the short hand which denotes the number of hours, makes 2 revolutions around the clock. Its distance traveled would be twice the perimeter of the circle.
Distance traveled by hour hand = 2(2πr) = 4πr₁
In 60 s, the long hand, which denotes numbers of minutes, makes one revolution around the clock. Since there are 86,400 seconds in a day, that would be a total of 1,440 revolutions.
Distance traveled by minute hand = 1,440(2πr) = 2,880πr₂
Difference = 2880πr₂ - 4πr₁ = 4π(720r₂ - r₁), where r₁ is the length of hour hand and r₂ is the length of minute hand.
105 is the product of 15 and 7.
