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Rzqust [24]
3 years ago
13

The number of fish (f) in a fish tank increases when the number of algae blooms (a) decreases. Write the correct equation for th

is scenario, and solve for the number of fish when there are 4 algae blooms. Algae Blooms Fish 10 10 25 4
Mathematics
1 answer:
Artyom0805 [142]3 years ago
6 0

Answer:

  • f = -2/5a +14
  • 12.4 ≈ 12 fish for 4 algae blooms

Step-by-step explanation:

The 2-point form of the equation for a line is useful when you are given two points to work with:

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

The independent variable (x) is apparently "algae blooms" and is to be represented by "a". The dependent variable (y) is "number of fish" and is to be represented by "f". So, we have ...

  f = (4 -10)/(25 -10)(a -10) +10

  f = -6/15(a -10) +10

  f = -2/5a +14 . . . an equation for the scenario

Four a=4, the fish population is predicted to be ...

  f = -2/5(4) +14 = 12.4

There will be about 12 fish when there are 4 algae blooms.

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7 0
3 years ago
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The area of the surface of a sphere is described by the formula S=4(3.14)r^2. The earth has a radius of 3960 miles and dry land
Stella [2.4K]

Answer: 57,512,581.63miles^2

Step-by-step explanation:

Substitute the value of the radius of the Earth into the formula given in the problem, where r is the radius, to obtain the surface area of the Earth:

S=4(3.14)r^2\\S=4(3.14)(3,960miles)^2\\S=196,960,896miles^2

The problem says that the dry land forms 29.2% of the Earth’s surface, therefore, multiply the surface area by \frac{29.2}{100}=0.292

Threfore, the area of dry land is the following:

S_{land}=(0.292)(196,960,896miles^2)=57,512,581.63miles^2

8 0
3 years ago
5. a : 4, for a = 32
Dmitrij [34]

Answer:

8

Step-by-step explanation:

put 4 in place for a

4=32

dive both sides by 4 and you will get 8

hope this helps

8 0
3 years ago
Question 2: Jamie has a jar of coins containing the same number of nickels, dimes and quarters. The total value of the coins in
Murrr4er [49]

Answer:

?

Step-by-step explanation:

8 0
3 years ago
if a pair of standard dice are rolled what is the probability that one die shows a six but not both of them. reduced fraction an
Novay_Z [31]

Answer:

P=\frac{5}{18}

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.  

The size of the sample space is the total number of possible outcomes  

The event space is the number of outcomes in the event you are interested in.  

so  

Let

x------> size of the event space

y-----> size of the sample space  

if a die is rolled the sample space is

\{1,2,3,4,5,6\}

if two dice rolled the sample space is

\{1,2,3,4,5,6\}*\{1,2,3,4,5,6\}

so

The possible pairs are

y=6*6=36

The size of the event space x is

\{(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5)\}

x=10

P=\frac{x}{y}

substitute

P=\frac{10}{36}

Simplify

P=\frac{5}{18}

6 0
3 years ago
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