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Usimov [2.4K]
2 years ago
6

Which of the following is a solution to the equation c+(4-3c)-2=0

Mathematics
1 answer:
Eduardwww [97]2 years ago
3 0

Answer:

c=1

Step-by-step explanation:

You might be interested in
Mathematics Areas and perimeters ​
sweet-ann [11.9K]

Answer:

54.5 Sq. cm

Step-by-step explanation:

<em>area of a right angled triangle = 1/ 2 × base × height </em>

(here, the base is 8 and height is 6)

= 1/ 2 × 6 × 8

= 4 × 6

<u>= 24 Sq. cm</u>

<em>area of a circle</em> = \pi r²

(r is the radius that is diameter/ 2, and the value of \pi is 3. 14)

  • r = 10/ 2 = 5 cm

= 3. 14.× (5)²

= 3.14 × 25

<u>= 78.5 Sq. cm</u>

area of the shaded region = area of Circle - area of triangle

= 78.5 - 24

<h3>= 54.5 Sq. cm</h3>

that is option 3

7 0
2 years ago
What is the length of the arc on a circle with radius 20 in. intercepted by a 15° angle? Use 3.14 for π . Round the answer to th
Fofino [41]
We know, length of arc = Ф/360 * 2πr
= 15/360 * (2 * 3.14 * 20)
= 1/24 * (125.6)
= 5.23

In short, Your Answer would be 5.23 Inches

Hope this helps!
5 0
3 years ago
Holly spends 7 3/5 hours in school each day. Her lunch is 1/2 hour long, and she spends 7/10 of a hour switching classes. The re
Ira Lisetskai [31]
<span>
y = 7 + 3/5
y = 35/5 + 3/5
y = 38/5
y = 2*(38/5)
y = 76/10
---
lunch time:
z = 1/2
z = 5*(1/2)
z = 5/10
---
time switching classes:
w = 7/10
---
y - 6x - z - w = 0
6x = y - z - w
x = (y - z - w)/6
x = (76/10 - 5/10 - 7/10)/6
x = (76 - 5 - 7)/(10*6)
x = (64)/(10*6)
x = (2*2*2*2*2*2)/(2*5*2*3)
x = (2*2*2*2)/(5*3)
x = 16/15

x = 1.0666666666
---
check:
y = 7 + 3/5
y = 7.6
z = 1/2
z = 0.5
w = 7/10
w = 0.7
y - 6x - z - w = 0
6x = y - z - w
x = (y - z - w)/6
x = (7.6 - 0.5 - 0.7)/6
x = 1.0666666666

answer:
 1.07 hours</span>
5 0
3 years ago
Find the length of segment AB.
12345 [234]
The answer is D.
explain:
A^2 + b^2 = c^2
8 0
3 years ago
Read 2 more answers
In the equation x^2+10x+24=(x+a)(x+b), b is an integer. Find algebraically all possible values of b
Vinil7 [7]
(x+4)(x+6)
(x+6)(x+4) 

8 0
3 years ago
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