A) the greatest common factor is y^2 so
y^2(3x^2-x-2)
...
B) x^2+6x+9
x^2+3x+3x+9
x(x+3)+3(x+3)
(x+3)(x+3)
(x+3)^2
C)
x^2-25
x^2-5x+5x-25
x(x-5)+5(x-5)
(x+5)(x-5)
Let 
be the short, medium and long side, respectively. If we translate all the information into formulas, we get the following system:
Using the second equation, we can express the middle side in terms of the small one, and reduce the system to two equations in two unknowns:
And thus
But then again, using the first equation, the third becomes
So, the longest side is 12. Since the small is half the long, we have 
. Finally, the medium is three more of the small, so we have 
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Answer:
25 i think
Step-by-step explanation:
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Answer:
m∠C = 102°
Step-by-step explanation:
This diagram is a Quadrilateral inscribed in a circle
The first step is to determine what m∠B
is
The sum of opposite angles in an inscribed quadrilateral is equal to 180°
m∠D + m∠B = 180°
m∠B = 180° - m∠D
m∠B = 180° - 80°
m∠B = 100°
Second step is we proceed to determine the exterior angles of the circle
m∠ADC = 2 × m∠B
m∠ADC = 2 × 100°
m∠ADC = 200°
m∠ADC = m∠CD + m∠AD
m∠AD = m∠ADC - m∠CD
m∠AD = 200° - 116°
m∠AD = 84°
The third step is to determine m∠BAD
m∠BAD = m∠AD + m∠AB
m∠BAD = 84° + 120°
m∠BAD = 204°
The final step Is to determine what m∠C is
It is important to note that:
m∠BAD is Opposite m∠C
Hence
m∠C = 1/2 × m∠BAD
m∠C = 1/2 × 204
m∠C = 102°
