Interesting question. Good to know for computer science.
Suppose you have a function like
an = 3x - 2 Try the first couple
a1 = 3(1) - 2
a1 = 3 - 2
a1 = 1
a2 = 3(2) - 2
a2 = 6 - 2
a2 = 4 So each term differs by 3
a2 - a1 = 3
an = a_(n - 1) + 3
a3 = a2 + 3
a3 = 4 + 3
a3 = 7
a4 = a3 + 3
a4 = 7 + 3
a4 = 10
a5 = a4+ 3
a5 = 10 + 3
a5 = 13
I'll do one more and then check it.
a6 = a5 + 3
a6 = 13 + 3
a6 = 16
a6 = 3x -2
a6 = 3*6 - 2
a6 = 18 - 2
a6 = 16 which checks.
So the general formula is
an = a_(n - 1) * k if you were multiplying or
an = a_(n - 1) + k if you were adding. The key thing is that you are working with the previous term.
Answer:
Amaro
Step-by-step explanation:
Its the fourth one hope this helps
Answer:
a = 12
Step-by-step explanation:
∠OPQ is a right angle.
![5^{2} + a^{2} = 13^{2} \\25 + a^{2} = 169\\a^{2} = 144\\a = 12](https://tex.z-dn.net/?f=5%5E%7B2%7D%20%2B%20a%5E%7B2%7D%20%20%3D%2013%5E%7B2%7D%20%5C%5C25%20%2B%20a%5E%7B2%7D%20%20%3D%20169%5C%5Ca%5E%7B2%7D%20%3D%20144%5C%5Ca%20%3D%2012)
$21.00
Step-by-step explanation:
if 1 yard equal 6 dollars
do 6 times 3 = 18
and half of 6 is 3
add 18+3=21 dollars